I'm trying to become familiar with sed by extracting email address from input in the following form:
我试图通过从以下形式的输入中提取电子邮件地址来熟悉sed:
something_from.someone:user@email.com
something_from.someone:user.com
That is the input I'm sending to sed, I'm trying to remove everything up to and including ::
这是我发送给sed的输入，我正在尝试删除所有内容，包括:
sed 'd/[[alphanum:]]+[.][[:alphanum:]]+[:]//'
Based on my research, this should do it, but I'm getting this error:
根据我的研究，这应该可以做到，但我犯了这个错误:
sed: 1: "d/[[:alphanum:]]+[.][[: ...": extra characters at the end of d command
sed:1:“d /[[:alphanum:]]+[。][[:……: d命令末尾的额外字符
Any ideas as to what I'm doing incorrectly?
你知道我做错了什么吗?
1 个解决方案
#1
3
Your delete syntax is incorrect. To delete in sed you need to do:
删除语法不正确。在sed中删除您需要做的:
sed '(separator) [pattern to delete](separator)d'
Thus, for example:
因此,例如:
sed -e '/regex/d' infile
This is for deleting whole lines generally. What you want to do instead is keep some part of the line so you need a capture-and-replace:
这是为了一般地删除整行。相反，你想做的是保留一部分内容，这样你就需要一个“捕获-替换”:
sed -e 's/regex-to-drop\(regex-to-keep\)/\1/g' input-file
The 's' is for substitute and the 'g' is for global, and the \( \) is what is captured while the \1 is where I want the captured thing to go. If I had a series of captured items,
“s”代表替换，“g”代表全局，“\(\)”代表捕获，而“\1”代表捕获对象。如果我有一系列被捕获的项目，
\(something\)\(something_else\)
I could reproduce them with another character between them by simply putting the following in the substitute part of the sed command:
只要在sed命令的替换部分中输入以下内容，我就可以用它们之间的另一个字符复制它们:
\1 ;; \2
This would produce: something ;; something_else and altogether would look like:
这将产生:某种东西;其他一些东西和整体看起来会是这样的:
sed -e 's/\(something\)\(something_else\)/\1 ;; \2/g' input-file
In your case, it looks like you want to drop everything before the colon:
在你的例子中，看起来你想把所有东西都放在冒号之前:
sed -e 's/^.*:\(.*\)$/\1/g' input-file
Footnote to the above as suggested by @fedorqui:
@fedorqui的脚注:
Sed uses standard regex notation to refer to the beginning and end of a line, so "^" refers to the beginning of the line and "$" refers to the end of the line. Thus, the complete explanation of the above is as follows:
Sed使用标准的正则表达式符号指代一行的开始和结束,所以“^”是指线的开始和结束的“美元”是指线。因此，对上述问题的完整解释如下:
's/^.*:
Everything from the start of the line up to the colon (the "s" means we're setting up a 'substitute' command).
从行开始到冒号(“s”表示我们正在设置一个“替换”命令)。
Then:
然后:
\(.*\)$/
CAPTURE everything up to the end of the line, and
捕捉到一行末尾的所有内容
/\1/g'
Substitute the WHOLE line with the captured item. Do it globally (for the whole file).
用捕获的项替换整个行。全局执行(对于整个文件)。
#1
3
Your delete syntax is incorrect. To delete in sed you need to do:
删除语法不正确。在sed中删除您需要做的:
sed '(separator) [pattern to delete](separator)d'
Thus, for example:
因此,例如:
sed -e '/regex/d' infile
This is for deleting whole lines generally. What you want to do instead is keep some part of the line so you need a capture-and-replace:
这是为了一般地删除整行。相反，你想做的是保留一部分内容，这样你就需要一个“捕获-替换”:
sed -e 's/regex-to-drop\(regex-to-keep\)/\1/g' input-file
The 's' is for substitute and the 'g' is for global, and the \( \) is what is captured while the \1 is where I want the captured thing to go. If I had a series of captured items,
“s”代表替换，“g”代表全局，“\(\)”代表捕获，而“\1”代表捕获对象。如果我有一系列被捕获的项目，
\(something\)\(something_else\)
I could reproduce them with another character between them by simply putting the following in the substitute part of the sed command:
只要在sed命令的替换部分中输入以下内容，我就可以用它们之间的另一个字符复制它们:
\1 ;; \2
This would produce: something ;; something_else and altogether would look like:
这将产生:某种东西;其他一些东西和整体看起来会是这样的:
sed -e 's/\(something\)\(something_else\)/\1 ;; \2/g' input-file
In your case, it looks like you want to drop everything before the colon:
在你的例子中，看起来你想把所有东西都放在冒号之前:
sed -e 's/^.*:\(.*\)$/\1/g' input-file
Footnote to the above as suggested by @fedorqui:
@fedorqui的脚注:
Sed uses standard regex notation to refer to the beginning and end of a line, so "^" refers to the beginning of the line and "$" refers to the end of the line. Thus, the complete explanation of the above is as follows:
Sed使用标准的正则表达式符号指代一行的开始和结束,所以“^”是指线的开始和结束的“美元”是指线。因此，对上述问题的完整解释如下:
's/^.*:
Everything from the start of the line up to the colon (the "s" means we're setting up a 'substitute' command).
从行开始到冒号(“s”表示我们正在设置一个“替换”命令)。
Then:
然后:
\(.*\)$/
CAPTURE everything up to the end of the line, and
捕捉到一行末尾的所有内容
/\1/g'
Substitute the WHOLE line with the captured item. Do it globally (for the whole file).
用捕获的项替换整个行。全局执行(对于整个文件)。