使用python搜索和替换xml / text文件中的多行

时间:2022-03-15 16:51:32

---Update 3: I have got the script to update the required data into the xml files completed but the following code is being dropped from the written file. Why is this? how can I replace it?

---更新3:我有脚本将所需数据更新为已完成的xml文件,但以下代码将从写入的文件中删除。为什么是这样?我该怎么替换它?

<?xml version="1.0" encoding="utf-8"?><?xml-stylesheet type='text/xsl' href='ANZMeta.xsl'?>

Current working code (except for issue mentioned above).

当前的工作代码(上述问题除外)。

import os, xml, arcpy, shutil
from xml.etree import ElementTree as et 

path=os.getcwd()
arcpy.env.workspace = path

FileList = arcpy.ListFeatureClasses()
FileCount = len(FileList)
zone="_Zone"

for File in FileList:
    FileDesc_obj = arcpy.Describe(File)
    FileNm=FileDesc_obj.file
    newMetaFile=FileNm+"_BaseMetadata.xml"

    check_meta=os.listdir(path)
    if FileNm+'.xml' in check_meta:
        shutil.copy2(FileNm+'.xml', newMetaFile)
    else:
        shutil.copy2('L:\Data_Admin\QA\Metadata_python_toolset\Master_Metadata.xml', newMetaFile)
    tree=et.parse(newMetaFile)

    print "Processing: "+str(File)

    for node in tree.findall('.//title'):
        node.text = str(FileNm)
    for node in tree.findall('.//northbc'):
        node.text = str(FileDesc_obj.extent.YMax)
    for node in tree.findall('.//southbc'):
        node.text = str(FileDesc_obj.extent.YMin)
    for node in tree.findall('.//westbc'):
        node.text = str(FileDesc_obj.extent.XMin)
    for node in tree.findall('.//eastbc'):
        node.text = str(FileDesc_obj.extent.XMax)        
    for node in tree.findall('.//native/nondig/formname'):
        node.text = str(os.getcwd()+"\\"+File)
    for node in tree.findall('.//native/digform/formname'):
        node.text = str(FileDesc_obj.featureType)
    for node in tree.findall('.//avlform/nondig/formname'):
        node.text = str(FileDesc_obj.extension)
    for node in tree.findall('.//avlform/digform/formname'):
        node.text = str(float(os.path.getsize(File))/int(1024))+" KB"
    for node in tree.findall('.//theme'):
        node.text = str(FileDesc_obj.spatialReference.name +" ; EPSG: "+str(FileDesc_obj.spatialReference.factoryCode))
    print node.text
    projection_info=[]
    Zone=FileDesc_obj.spatialReference.name

    if "GCS" in str(FileDesc_obj.spatialReference.name):
        projection_info=[FileDesc_obj.spatialReference.GCSName, FileDesc_obj.spatialReference.angularUnitName, FileDesc_obj.spatialReference.datumName, FileDesc_obj.spatialReference.spheroidName]
        print "Geographic Coordinate system"
    else:
        projection_info=[FileDesc_obj.spatialReference.datumName, FileDesc_obj.spatialReference.spheroidName, FileDesc_obj.spatialReference.angularUnitName, Zone[Zone.rfind(zone)-3:]]
        print "Projected Coordinate system"
    x=0
    for node in tree.findall('.//spdom'):
        for node2 in node.findall('.//keyword'):
            print node2.text
            node2.text = str(projection_info[x])
            print node2.text
            x=x+1


    tree.write(newMetaFile)

---Update 1&2: Thanks to Aleyna I have the following basic code that works

---更新1和2:感谢Aleyna我有以下基本代码可行

import os, xml, arcpy, shutil
from xml.etree import ElementTree as et 

CodeString=['northbc','southbc', '<nondig><formname>']

nondig='nondigital'
path=os.getcwd()
arcpy.env.workspace = path
xmlfile = path+"\\test.xml"

FileList = arcpy.ListFeatureClasses()
FileCount = len(FileList)

for File in FileList:
    FileDesc_obj = arcpy.Describe(File)
    FileNm=FileDesc_obj.file
    newMetaFile=FileNm+"_Metadata.xml"
    shutil.copy2('L:\Data_Admin\QA\Metadata_python_toolset\Master_Metadata.xml', newMetaFile)
    tree=et.parse(newMetaFile)

    for node in tree.findall('.//northbc'):
        node.text = str(FileDesc_obj.extent.YMax)
    for node in tree.findall('.//southbc'):
        node.text = str(FileDesc_obj.extent.YMin)
    for node in tree.findall('.//westbc'):
        node.text = str(FileDesc_obj.extent.XMin)
    for node in tree.findall('.//eastbc'):
        node.text = str(FileDesc_obj.extent.XMax)        
    for node in tree.findall('.//native/nondig/formname'):
        node.text = nondig

    tree.write(newMetaFile)

The issue is with dealing with xml code like

问题在于处理像xml这样的代码

- <spdom>
  <keyword thesaurus="">GDA94</keyword> 
  <keyword thesaurus="">GRS80</keyword> 
  <keyword thesaurus="">Transverse Mercator</keyword> 
  <keyword thesaurus="">Zone 55 (144E - 150E)</keyword> 
  </spdom>

As keyword thes...is not unique within the <spdom> can we update these in a order from the values coming from

由于关键字thes ...在 中不是唯一的,我们可以按照来自的值的顺序更新这些

FileDesc_obj.spatialReference.name

u'GCS_GDA_1994'

---ORIGINAL POST---

I am building up a program to generate xml metadata files from spatial files in our library. I have already created the scripts to extract the required spatial and attrib data from the files and create a shp and text file based index of the files but now I want to write this info to base metadata xml file that is written to anzlic standards by replacing the values held by common/static elements...

我正在构建一个程序来从我们库中的空间文件生成xml元数据文件。我已经创建了脚本来从文件中提取所需的空间和属性数据,并创建基于shp和文本文件的文件索引,但现在我想将此信息写入基本元数据xml文件,通过替换写入anzlic标准共同/静态元素所持有的价值......

So for example I want to replace the following xml code

所以例如我想替换下面的xml代码

<northbc>8097970</northbc>
<southbc>8078568</southbc>

with

<northbc> GeneratedValue_[desc.extent.XMax] /<northbc>
<southbc> GeneratedValue_[desc.extent.XMax] </southbc>

The issue is that obviously the number/value between and will not be the same.

问题是,显然数字/值之间和之间的数字/值不一样。

Similarly for xml tags like <title>, <nondig><formname> etc...in the latter example both tags must be searched for together as formname appears multiple times (is not unique).

类似地,对于xml标签,例如

, 等......在后一示例中,两个标签必须一起搜索,因为formname多次出现(不是唯一的)。

I am using the Python Regular Expression manual [here][1],

我正在使用Python正则表达式手册[这里] [1],

3 个解决方案

#1


2  

Using the given tag(s) above:

使用上面给定的标签:

import os
import xml
from xml.etree import ElementTree as et 
path = r"/your/path/to/xml.file" 
tree = et.parse(path)
for node in tree.findall('.//northbc'):
    node.text = "New Value"
tree.write(path)

Here, XPATH .//northbc returns all the 'northbc' nodes in the XML doc. You can tailor the code for your need easily.

这里,XPATH .//northbc返回XML文档中的所有“northbc”节点。您可以轻松地根据需要定制代码。

#2


1  

If you're dealing with valid XML, use XPath to find the nodes of interest and the ElementTree api to manipulate the node.

如果您正在处理有效的XML,请使用XPath查找感兴趣的节点,使用ElementTree api来操作节点。

For instance, your xpath might be something like '//northbc' and you would just replace the text node inside it.

例如,您的xpath可能类似于“// northbc”,您只需替换其中的文本节点即可。

See http://docs.python.org/library/xml.etree.elementtree.html as well as http://pypi.python.org/pypi/lxml/2.2.8 for two different libraries that will help you get this done. Search google for XPath and see the w3c tutorial for a decent intro to XPath (I apparently can't post more than two links in a post or I'd link it too)

有关两个不同的库,请参阅http://docs.python.org/library/xml.etree.elementtree.html以及http://pypi.python.org/pypi/lxml/2.2.8。完成。搜索google for XPath并查看w3c教程以获得一个体面的XPath介绍(我显然不能在帖子中发布超过两个链接或我也链接它)

#3


0  

I might be stating the obvious here, but did you consider using a DOM tree to parse and manipulate your XML?

我可能会在这里说明显而易见的,但您是否考虑过使用DOM树来解析和操作XML?

#1


2  

Using the given tag(s) above:

使用上面给定的标签:

import os
import xml
from xml.etree import ElementTree as et 
path = r"/your/path/to/xml.file" 
tree = et.parse(path)
for node in tree.findall('.//northbc'):
    node.text = "New Value"
tree.write(path)

Here, XPATH .//northbc returns all the 'northbc' nodes in the XML doc. You can tailor the code for your need easily.

这里,XPATH .//northbc返回XML文档中的所有“northbc”节点。您可以轻松地根据需要定制代码。

#2


1  

If you're dealing with valid XML, use XPath to find the nodes of interest and the ElementTree api to manipulate the node.

如果您正在处理有效的XML,请使用XPath查找感兴趣的节点,使用ElementTree api来操作节点。

For instance, your xpath might be something like '//northbc' and you would just replace the text node inside it.

例如,您的xpath可能类似于“// northbc”,您只需替换其中的文本节点即可。

See http://docs.python.org/library/xml.etree.elementtree.html as well as http://pypi.python.org/pypi/lxml/2.2.8 for two different libraries that will help you get this done. Search google for XPath and see the w3c tutorial for a decent intro to XPath (I apparently can't post more than two links in a post or I'd link it too)

有关两个不同的库,请参阅http://docs.python.org/library/xml.etree.elementtree.html以及http://pypi.python.org/pypi/lxml/2.2.8。完成。搜索google for XPath并查看w3c教程以获得一个体面的XPath介绍(我显然不能在帖子中发布超过两个链接或我也链接它)

#3


0  

I might be stating the obvious here, but did you consider using a DOM tree to parse and manipulate your XML?

我可能会在这里说明显而易见的,但您是否考虑过使用DOM树来解析和操作XML?