GNU Sed REGEX查找并更改字符串（无替换）

I have the followinf text:

我有以下文字：

11 Cherrywood Rise Ashford Kent TN25 4QA United Kingdom N B BONE 02/12 387
Bisham village Bisham Buckinghamshire SL7 1RR United Kingdom Neil Noakes 06/13 488
6 Kynaston Road London London N16 0EX United Kingdom MR N P SALTMARSH 04/13 907
116 Long Acre London London WC2E 9SU United Kingdom Lorna J Gradden 11/14 415

How can I use sed to match the dates "mm/yy" format and alter to "|mm/yy|"

如何使用sed匹配日期“mm / yy”格式并更改为“| mm / yy |”

Like: 11 Cherrywood Rise Ashford Kent TN25 4QA United Kingdom N B BONE|02/12|387

喜欢：11 Cherrywood Rise Ashford Kent TN25 4QA英国N B BONE | 02/12 | 387

Thanks!

谢谢！

2 个解决方案

#1

does this work for you?

这对你有用吗？

sed -r 's# ([0-9]{2}/[0-9]{2}) #|\1|#' file

#2

Example 1

例1

cat t.txt | sed -E 's/([0-9]{2}\/[0-9]{2})/|\1|/g'

11 Cherrywood Rise Ashford Kent TN25 4QA United Kingdom N B BONE (02/12) 387 Bisham village Bisham Buckinghamshire SL7 1RR United Kingdom Neil Noakes (06/13) 488 6 Kynaston Road London London N16 0EX United Kingdom MR N P SALTMARSH (04/13) 907 116 Long Acre London London WC2E 9SU United Kingdom Lorna J Gradden (11/14) 415

11 Cherrywood Rise Ashford Kent TN25 4QA英国NB BONE（02/12）387 Bisham village Bisham Buckinghamshire SL7 1RR United Kingdom Neil Noakes（06/13）488 6 Kynaston Road London London N16 0EX United Kingdom MR NP SALTMARSH（04/13） 907 116 Long Acre London London WC2E 9SU英国Lorna J Gradden（11/14）415

要么

sed -E 's/([0-9]{2}\/[0-9]{2})/|\1|/g' t.txt

#1

does this work for you?

这对你有用吗？

sed -r 's# ([0-9]{2}/[0-9]{2}) #|\1|#' file

#2

Example 1

例1

cat t.txt | sed -E 's/([0-9]{2}\/[0-9]{2})/|\1|/g'

要么

sed -E 's/([0-9]{2}\/[0-9]{2})/|\1|/g' t.txt

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GNU Sed REGEX查找并更改字符串（无替换）

2 个解决方案

#1

#2

#1

#2

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