如何用空白sed替换一些彩色字符[复制]

This question already has an answer here:

这个问题在这里已有答案：

How to remove ^[, and all of the escape sequences in a file using linux shell scripting 8 answers
如何使用linux shell脚本8答案删除^ [，以及文件中的所有转义序列

I am trying to replace some sequence of character with a blank. But I am not able to replace it.

我试图用空白替换一些字符序列。但我无法取代它。

File name is Test:

文件名是Test：

id       ^[[0mevent^[[0m            ^[[0msuite^[[0m                                     ^[[0mok^[[0m     ^[[0mnok^[[0m    ^[[0mskip^[[0m  test  up        owner     du     duplex  type   stp             inst_type  prep  created              finished

I am trying to replace ^[[0m with a blank character. To do so I am using the following command to achieve the aforementioned task.

我试图替换^ [[0m与空白字符。为此，我使用以下命令来完成上述任务。

sed 's/\^\[\[0m//g' Test

However, the above command is having not impact.

但是，上述命令没有影响。

The problem is due to coloured font.

问题是由于彩色字体。

Thanks!!

谢谢！！

2 个解决方案

#1

You are replacing it with z just remove the z also instead of 0 seems that you have typed big O. Change it to 0 then it will work very well:

您正在用z替换它只是删除z而不是0似乎您已经键入了大O.将其更改为0然后它将工作得很好：

~$ echo "id       ^[[0mevent^[[0m            ^[[0msuite^[[0m"|sed 's/\^\[\[0m//g'
id       event            suite

#2

I have used the following command to replace the colored text:

我使用以下命令替换彩色文本：

sed -r "s/\x1B\[([0-9]{1,2}(;[0-9]{1,2})?)?[m|K]//g" abc

Source: http://www.commandlinefu.com/commands/view/3584/remove-color-codes-special-characters-with-sed

资料来源：http：//www.commandlinefu.com/commands/view/3584/remove-color-codes-special-characters-with-sed

#1