sed awk用模式匹配替换行

With awk or sed how could I replace each line after a pattern match? the pattern would always start as S:\ and something else, I need the entire line from S:\~ to the end to appear on the next lines before a blank line.

使用awk或sed如何在模式匹配后替换每一行?模式总是以S:\和其他东西开始,我需要从S:\〜到最后的整行出现在空白行之前的下一行。

I have an input like this:

我有这样的输入:

S:\dir1\subfolder1longsubf
abcdefg
1234567
permissions

S:\dir2\verylongsub
some random string
some random string

S:\dir3
some random string
some random string

S:\dir4\sub2\sub3
some random string
some random string
some random string

and I need an ouput like this:

我需要这样的输出:

S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf

S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir2\verylongsub

S:\dir3
S:\dir3
S:\dir3

S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3

2 个解决方案

#1

I would use awk:

我会用awk:

awk '/^S/ {line=$0} {print NF?line:""}' file

This stores the line starting with S. Then, it prints either this stored value or an empty line if the line is empty.

这将存储以S开头的行。然后,如果该行为空,则打印此存储的值或空行。

Test

$ awk '/^S/ {line=$0} {print NF?line:""}' file
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf

S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir2\verylongsub

S:\dir3
S:\dir3
S:\dir3

S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3

#2

With GNU sed:

使用GNU sed:

sed  '/^S:/{h};/^[^S]/{g}' file