how to sed replace whole line with the string as variable ?
如何用字符串替换整行作为变量？
#!/bin/bash
ssh $1 ssh-keyscan -t rsa $1 > /tmp/$1
RSA=$(cat /tmp/$1)
echo $RSA
sed -i 's:'^"$1".*':'"$RSA"':' /etc/ssh/ssh_known_hosts
cat /etc/ssh/ssh_known_hosts | grep $1
It is storing the variable in RSA but not replacing, not sure what's wrong with sed part.
它将变量存储在RSA中但不替换，不确定sed部分有什么问题。
1 个解决方案
#1
2
You can use the following command.
您可以使用以下命令。
#!/bin/bash
ssh $1 ssh-keyscan -t rsa $1 > /tmp/$1
RSA=$(cat /tmp/$1)
echo $RSA
sed -i -e "/$1/ d" -e "/^$1/ a $RSA" /etc/ssh/ssh_known_hosts
cat /etc/ssh/ssh_known_hosts | grep $1
I modified as per your requirement to add if not line exists and replace if it exists.
我根据您的要求修改了如果不存在行则添加，如果存在则替换。
#1
2
You can use the following command.
您可以使用以下命令。
#!/bin/bash
ssh $1 ssh-keyscan -t rsa $1 > /tmp/$1
RSA=$(cat /tmp/$1)
echo $RSA
sed -i -e "/$1/ d" -e "/^$1/ a $RSA" /etc/ssh/ssh_known_hosts
cat /etc/ssh/ssh_known_hosts | grep $1
I modified as per your requirement to add if not line exists and replace if it exists.
我根据您的要求修改了如果不存在行则添加，如果存在则替换。