I created a custom group in Django's admin site.
我在Django的管理站点中创建了一个自定义组。
In my code, I want to check if a user is in this group. How do I do that?
在我的代码中,我想检查用户是否在这个组中。我该怎么做呢?
10 个解决方案
#1
73
You can access the groups simply through the groups
attribute on User
.
您可以通过用户上的groups属性访问组。
from django.contrib.auth.models import User, Group
group = Group(name="Editor")
group.save() # save this new group for this example
user = User.objects.get(pk=1) # assuming, there is one initial user
user.groups.add(group) # user is now in the "Editor" group
then user.groups.all()
returns [<Group: Editor>]
然后user.groups.all()返回[
#2
150
Your User object is linked to the Group object through a ManyToMany relationship.
您的用户对象通过许多tomany关系链接到组对象。
You can thereby apply the filter method to user.groups.
因此,您可以将filter方法应用到user.groups。
So, to check if a given User is in a certain group ("Member" for the example), just do this :
因此,要检查给定用户是否属于某个组(例如“Member”),只需这样做:
def is_member(user):
return user.groups.filter(name='Member').exists()
If you want to check if a given user belongs to more than one given groups, use the __in operator like so :
如果要检查给定用户是否属于多个给定组,请使用__in操作符,如:
def is_in_multiple_groups(user):
return user.groups.filter(name__in=['group1', 'group2']).exists()
Note that those functions can be used with the @user_passes_test decorator to manage access to your views :
注意,这些函数可以与@user_passes_test decorator一起使用,以管理对视图的访问:
from django.contrib.auth.decorators import login_required, user_passes_test
@login_required
@user_passes_test(is_member) # or @user_passes_test(is_in_multiple_groups)
def myview(request):
# Do your processing
Hope this help
希望这有助于
#3
12
If you don't need the user instance on site (as I did), you can do it with
如果您不需要站点上的用户实例(如我所做的),您可以使用它
User.objects.filter(pk=userId, groups__name='Editor').exists()
This will produce only one request to the database and return a boolean.
这将只向数据库生成一个请求并返回一个布尔值。
#4
11
If you need the list of users that are in a group, you can do this instead:
如果您需要一个组中的用户列表,您可以这样做:
from django.contrib.auth.models import Group
users_in_group = Group.objects.get(name="group name").user_set.all()
and then check
然后检查
if user in users_in_group:
# do something
to check if the user is in the group.
检查用户是否在组中。
#5
9
If a user belongs to a certain group or not, can be checked in django templates using:
如果用户是否属于某个组,可以在django模板中使用:
{% if group in request.user.groups.all %}
"some action"
{% endif %}
{% if group in request.user.groups。所有%}"some action" {% endif %}
#6
7
You just need one line:
你只需要写一行:
from django.contrib.auth.decorators import user_passes_test
@user_passes_test(lambda u: u.groups.filter(name='companyGroup').exists())
def you_view():
return HttpResponse("Since you're logged in, you can see this text!")
#7
0
Just in case if you wanna check user's group belongs to a predefined group list:
如果你想检查用户的组属于预定义的组列表:
def is_allowed(user):
allowed_group = set(['admin', 'lead', 'manager'])
usr = User.objects.get(username=user)
groups = [ x.name for x in usr.groups.all()]
if allowed_group.intersection(set(groups)):
return True
return False
#8
0
In one line:
一行:
'Groupname' in user.groups.values_list('name', flat=True)
This evaluates to either True
or False
.
这个计算结果为真或假。
#9
0
I have done it the following way. Seems inefficient but I had no other way in my mind:
我是这样做的。看起来效率不高,但我没有别的办法:
@login_required
def list_track(request):
usergroup = request.user.groups.values_list('name', flat=True).first()
if usergroup in 'appAdmin':
tracks = QuestionTrack.objects.order_by('pk')
return render(request, 'cmit/appadmin/list_track.html', {'tracks': tracks})
else:
return HttpResponseRedirect('/cmit/loggedin')
#10
0
User.objects.filter(username='tom', groups__name='admin').exists()
User.objects。过滤器(用户名=‘汤姆’,groups__name = '管理').exists()
That query will inform you user : "tom" whether belong to group "admin " or not
该查询将通知用户:“tom”是否属于组“admin”。
#1
73
You can access the groups simply through the groups
attribute on User
.
您可以通过用户上的groups属性访问组。
from django.contrib.auth.models import User, Group
group = Group(name="Editor")
group.save() # save this new group for this example
user = User.objects.get(pk=1) # assuming, there is one initial user
user.groups.add(group) # user is now in the "Editor" group
then user.groups.all()
returns [<Group: Editor>]
然后user.groups.all()返回[
#2
150
Your User object is linked to the Group object through a ManyToMany relationship.
您的用户对象通过许多tomany关系链接到组对象。
You can thereby apply the filter method to user.groups.
因此,您可以将filter方法应用到user.groups。
So, to check if a given User is in a certain group ("Member" for the example), just do this :
因此,要检查给定用户是否属于某个组(例如“Member”),只需这样做:
def is_member(user):
return user.groups.filter(name='Member').exists()
If you want to check if a given user belongs to more than one given groups, use the __in operator like so :
如果要检查给定用户是否属于多个给定组,请使用__in操作符,如:
def is_in_multiple_groups(user):
return user.groups.filter(name__in=['group1', 'group2']).exists()
Note that those functions can be used with the @user_passes_test decorator to manage access to your views :
注意,这些函数可以与@user_passes_test decorator一起使用,以管理对视图的访问:
from django.contrib.auth.decorators import login_required, user_passes_test
@login_required
@user_passes_test(is_member) # or @user_passes_test(is_in_multiple_groups)
def myview(request):
# Do your processing
Hope this help
希望这有助于
#3
12
If you don't need the user instance on site (as I did), you can do it with
如果您不需要站点上的用户实例(如我所做的),您可以使用它
User.objects.filter(pk=userId, groups__name='Editor').exists()
This will produce only one request to the database and return a boolean.
这将只向数据库生成一个请求并返回一个布尔值。
#4
11
If you need the list of users that are in a group, you can do this instead:
如果您需要一个组中的用户列表,您可以这样做:
from django.contrib.auth.models import Group
users_in_group = Group.objects.get(name="group name").user_set.all()
and then check
然后检查
if user in users_in_group:
# do something
to check if the user is in the group.
检查用户是否在组中。
#5
9
If a user belongs to a certain group or not, can be checked in django templates using:
如果用户是否属于某个组,可以在django模板中使用:
{% if group in request.user.groups.all %}
"some action"
{% endif %}
{% if group in request.user.groups。所有%}"some action" {% endif %}
#6
7
You just need one line:
你只需要写一行:
from django.contrib.auth.decorators import user_passes_test
@user_passes_test(lambda u: u.groups.filter(name='companyGroup').exists())
def you_view():
return HttpResponse("Since you're logged in, you can see this text!")
#7
0
Just in case if you wanna check user's group belongs to a predefined group list:
如果你想检查用户的组属于预定义的组列表:
def is_allowed(user):
allowed_group = set(['admin', 'lead', 'manager'])
usr = User.objects.get(username=user)
groups = [ x.name for x in usr.groups.all()]
if allowed_group.intersection(set(groups)):
return True
return False
#8
0
In one line:
一行:
'Groupname' in user.groups.values_list('name', flat=True)
This evaluates to either True
or False
.
这个计算结果为真或假。
#9
0
I have done it the following way. Seems inefficient but I had no other way in my mind:
我是这样做的。看起来效率不高,但我没有别的办法:
@login_required
def list_track(request):
usergroup = request.user.groups.values_list('name', flat=True).first()
if usergroup in 'appAdmin':
tracks = QuestionTrack.objects.order_by('pk')
return render(request, 'cmit/appadmin/list_track.html', {'tracks': tracks})
else:
return HttpResponseRedirect('/cmit/loggedin')
#10
0
User.objects.filter(username='tom', groups__name='admin').exists()
User.objects。过滤器(用户名=‘汤姆’,groups__name = '管理').exists()
That query will inform you user : "tom" whether belong to group "admin " or not
该查询将通知用户:“tom”是否属于组“admin”。