class test {
public $isNew;
public function isNew(){}
}
$ins = new test();
$ins->isNew
Here,how does php parse $ins->isNew
?
在这里,php如何解析$ ins-> isNew?
3 个解决方案
#1
25
PHP is not a functional programming language where functions are also data. So $ins->isNew
wouldn’t be ambiguous to either refer to the method isNew
or the attribute isNew
. $ins->isNew
is always an attribute and $ins->isNew()
a method call.
PHP不是函数编程语言,其中函数也是数据。所以$ ins-> isNew对于引用方法isNew或属性isNew不会有歧义。 $ ins-> isNew始终是一个属性,而$ ins-> isNew()是一个方法调用。
#2
5
$ins->isNew
is the variable. $ins->isNew()
is the function.
$ ins-> isNew是变量。 $ ins-> isNew()是函数。
#3
4
See the chapter on Class Basic in the PHP manual:
请参阅PHP手册中有关Class Basic的章节:
$ins->isNew // class member
$ins->isNew() // class method
#1
25
PHP is not a functional programming language where functions are also data. So $ins->isNew
wouldn’t be ambiguous to either refer to the method isNew
or the attribute isNew
. $ins->isNew
is always an attribute and $ins->isNew()
a method call.
PHP不是函数编程语言,其中函数也是数据。所以$ ins-> isNew对于引用方法isNew或属性isNew不会有歧义。 $ ins-> isNew始终是一个属性,而$ ins-> isNew()是一个方法调用。
#2
5
$ins->isNew
is the variable. $ins->isNew()
is the function.
$ ins-> isNew是变量。 $ ins-> isNew()是函数。
#3
4
See the chapter on Class Basic in the PHP manual:
请参阅PHP手册中有关Class Basic的章节:
$ins->isNew // class member
$ins->isNew() // class method