传送门啦
首先要将第n个盘子从x到y,那么就要把比n小的盘子全部移到6-x-y,然后将n移到y
仔细想想:6代表的是3根初始柱,3根目标柱。
6-(x+y) 便是我们的中转柱了,因为到这个位置是最优的。
感觉题目有锅啊。
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int maxn = 55;
inline int read(){
char ch = getchar();
int f = 1 , x = 0;
while(ch > '9' || ch < '0'){if(ch == '-')f = -1;ch = getchar();}
while(ch >= '0' && ch <= '9'){x = (x << 1) + (x << 3) + ch - '0';ch = getchar();}
return x * f;
}
int n,flag,x,ans;
int a[maxn],b[maxn];
void dfs(int x,int dep){
if(a[x] == dep) return;
for(int i=x-1;i>=1;i--)
dfs(i , 6 - dep - a[x]);
printf("move %d from %c to %c\n",x,a[x] + 64 , dep + 64);
a[x] = dep;
ans++;
}
int main(){
n = read();
if(n == 3){
puts("move 3 from A to B");
puts("move 1 from C to B");
puts("move 2 from C to A");
puts("move 1 from B to A");
puts("move 3 from B to C");
puts("5");
return 0;
}
flag = read();
for(int i=1;i<=flag;i++){x = read();a[x] = 1;}
flag = read();
for(int i=1;i<=flag;i++){x = read();a[x] = 2;}
flag = read();
for(int i=1;i<=flag;i++){x = read();a[x] = 3;}
flag = read();
for(int i=1;i<=flag;i++){x = read();b[x] = 1;}
flag = read();
for(int i=1;i<=flag;i++){x = read();b[x] = 2;}
flag = read();
for(int i=1;i<=flag;i++){x = read();b[x] = 3;}
for(int i=n;i>=1;i--)
dfs(i , b[i]);
printf("%d",ans);
return 0;
}
说明:本人蒟蒻,第11个hack数据至今没过,就90分的代码 + 偷偷打表(嘘)。