思路
求出cnt和len之后,直接乘起来即可
代码
#include <cstdio>
#include <algorithm>
#include <cstring>
#define int long long
using namespace std;
int Nodecnt,last,n,k;
signed trans[1001000][26],fail[1001000];
struct Node{
signed len,cnt;
bool operator < (const Node &b) const{
return len>b.len;
}
}a[1001000];
char s[1001000];
const int MOD = 19930726;
int pow(int a,int b){
int ans=1;
while(b){
if(b&1)
ans=(1LL*ans*a)%MOD;
a=(1LL*a*a)%MOD;
b>>=1;
}
return ans;
}
int New_state(int _len){
a[Nodecnt].len=_len;
return Nodecnt++;
}
int get_fail(int p,int n){
while(s[n]!=s[n-a[p].len-1])
p=fail[p];
return p;
}
void insert(int n){
int cur=get_fail(last,n);
if(!trans[cur][s[n]]){
int t=New_state(a[cur].len+2);
fail[t]=trans[get_fail(fail[cur],n)][s[n]];
trans[cur][s[n]]=t;
}
a[trans[cur][s[n]]].cnt++;
last=trans[cur][s[n]];
}
signed main(){
// freopen("test.in","r",stdin);
int ans=1;
scanf("%lld %lld",&n,&k);
scanf("%s",s+1);
s[0]=-1;
New_state(0);
fail[0]=1;
New_state(-1);
last=0;
for(int i=1;i<=n;i++){
s[i]-='a';
insert(i);
}
for(int i=Nodecnt-1;i>=0;i--)
a[fail[i]].cnt+=a[i].cnt;
sort(a,a+Nodecnt);
for(int i=0;i<Nodecnt&&k>0;i++){
if(a[i].len%2){
ans=(1LL*ans*pow(a[i].len,min(1LL*a[i].cnt,k)))%MOD;
k-=a[i].cnt;
}
}
printf("%lld\n",ans);
return 0;
}