I have a directory /a/b/c that has files and subdirectories. I need to copy the /a/b/c/* in the /x/y/z directory. What python methods can I use?

我有一个目录/a/b/c，有文件和子目录。我需要在/x/y/z目录中复制/a/b/c/*。我可以使用什么python方法?

I tried shutil.copytree("a/b/c", "/x/y/z"), but python tries to create /x/y/z and raises an error "Directory exists".

我试着shutil。copytree(“a/b/c”、“/x/y/z”)，但是python尝试创建/x/y/z，并引发一个错误“目录存在”。

4 个解决方案

#1

I found this code working.

我发现这段代码有效。

from distutils.dir_util import copy_tree

# copy subdirectory example
fromDirectory = "/a/b/c"
toDirectory = "/x/y/z"

copy_tree(fromDirectory, toDirectory)

Reference - https://docs.python.org/2/distutils/apiref.html#distutils.dir_util.copy_tree
引用——https://docs.python.org/2/distutils/apiref.html distutils.dir_util.copy_tree

#2

You can also use glob2 to recursively collect all paths (using ** subfolders wildcard) and then use shutil.copyfile, saving the paths

您还可以使用glob2来递归地收集所有路径(使用**子文件夹通配符)，然后使用shutil。拷贝文件,保存路径

glob2 link: https://code.activestate.com/pypm/glob2/

glob2链接:https://code.activestate.com/pypm/glob2/

#3

from subprocess import call

def cp_dir(source, target):
    call(['cp', '-a', source, target]) # Linux

cp_dir('/a/b/c/', '/x/y/z/')

It works for me. Basically, it executes shell command cp.

它适合我。基本上，它执行shell命令cp。

#4

-5

The python libs are obsolete with this function. I've done one that works correctly:

这个函数已经过时了。我做了一个正确的工作:

import os
import shutil

def copydirectorykut(src, dst):
    os.chdir(dst)
    list=os.listdir(src)
    nom= src+'.txt'
    fitx= open(nom, 'w')

    for item in list:
        fitx.write("%s\n" % item)

    fitx.close()

    f = open(nom,'r')
    for line in f.readlines():
        if "." in line:
            shutil.copy(src+'/'+line[:-1],dst+'/'+line[:-1])
        else:
            if not os.path.exists(dst+'/'+line[:-1]):
                os.makedirs(dst+'/'+line[:-1])
                copydirectorykut(src+'/'+line[:-1],dst+'/'+line[:-1])
            copydirectorykut(src+'/'+line[:-1],dst+'/'+line[:-1])
    f.close()
    os.remove(nom)
    os.chdir('..')

#1