使用带有对象名称[duplicate]的变量保存对象

Possible Duplicate:
how to save() with a particular variable name

可能重复：如何使用特定变量名保存（）

I'm wondering what an easy way is to save an object in R, using a variable objectName with the name of the object to be saved. I want this to easy save objects, with their name in the file name.

我想知道一个简单的方法是使用变量objectName和要保存的对象的名称来保存R中的对象。我希望这可以轻松保存对象，其名称在文件名中。

I tried to use get, but I didn't manage to save the object with it's original object name.

我试图使用get，但我没有设法用它的原始对象名称保存对象。

Example:

例：

If I have the object called "temp", which I want to save in the directory "dataDir". I put the name of the object in the variable "objectName".

如果我有一个名为“temp”的对象，我想将其保存在“dataDir”目录中。我将对象的名称放在变量“objectName”中。

Attempt 1:

尝试1：

objectName<-"temp"
save(get(objectName), file=paste(dataDir, objectName, ".RData", sep=""))
load(paste(dataDir, objectName, ".RData", sep=""))

This didn't work, because R tries to save an object called get(objectName), instead of the result of this call. So I tried the following:

这不起作用，因为R试图保存一个名为get（objectName）的对象，而不是这个调用的结果。所以我尝试了以下内容：

Attempt 2:

尝试2：

objectName<-"temp"
object<-get(objectName)
save(object, file=paste(dataDir, objectName, ".RData", sep=""))
load(paste(dataDir, objectName, ".RData", sep=""))

This obviously didn't work, because R saves the object with name "object", and not with name "temp". After loading I have a copy of "object", instead of "temp". (Yes, with the same contents...but that is not what I want :) ). So I thought it should be something with pointers. So tried the following:

这显然不起作用，因为R保存名为“object”的对象，而不是名称“temp”。加载后我有一个“对象”的副本，而不是“临时”。（是的，内容相同......但这不是我想要的:)）。所以我认为它应该是指针的东西。所以尝试了以下内容：

Attempt 3:

尝试3：

objectName<-"temp"
object<<-get(objectName)
save(object, file=paste(dataDir, objectName, ".RData", sep=""))
load(paste(dataDir, objectName, ".RData", sep=""))

Same result as attempt 2. But I'm not sure I'm doing what I think I'm doing.

与尝试2相同的结果。但我不确定我在做我认为我正在做的事情。

What is the solution for this?

这是什么解决方案？

2 个解决方案

#1

Try save(list=objectName, file=paste(objectName, '.Rdata', sep='') ).

尝试保存（list = objectName，file = paste（objectName，'。Rdata'，sep =''））。

The key is that the list argument to save takes a list of character strings that is the names of the objects to save (rather than the actual objects passed through ...).

关键是要保存的list参数采用一个字符串列表，这些字符串是要保存的对象的名称（而不是通过的实际对象...）。

#2

I found your examples hard to understand, but I can think of two possibilities of what you want. You either want the filename to be saved as objectName.RData or temp.RData. Here is how you do both:

我发现你的例子难以理解，但我可以想到你想要的两种可能性。您要么将文件名保存为objectName.RData或temp.RData。以下是您如何做到这两点：

objectName<-"temp"

# This saves the object as "temp.RData"
save(objectName, file=paste(dataDir, objectName, ".RData", sep=""))
# Loading it will bring it back with the name objectName, and the value temp
load(paste(dataDir, 'temp', '.RData', sep=''))

# This saves the object as "objectName.RData"
save(objectName, file=paste(dataDir, deparse(substitute(objectName)), ".RData",    sep=""))
# Loading it will bring it back with the name objectName, and the value temp
load(paste(dataDir, 'objectName', '.RData', sep=''))

All of your attempts return an error because you called the get incorrectly. It should have been get('objectName'), but if you think about it, that would get you exactly the same thing as objectName.

所有尝试都会返回错误，因为您错误地调用了get。它应该是get（'objectName'），但是如果你考虑它，那将会得到与objectName完全相同的东西。

#1