结果条件
在Java中,如果有重复的代码我们会考虑进行重构,抽取公共方法或继承父类,以减少相同的代码在多处出现,达到代码的最优管理和不必要的麻烦。Drools同样提供了类似的功能。下面我们以实例来逐步说明。
像下面最原始的两条规则,有相同的业务判断,也有不同的地方:
package com.rules.conditional
import com.secbro.drools.model.Customer;
import com.secbro.drools.model.Car;
rule "conditional1:Give 10% discount to customers older than 60"
agenda-group "conditional1"
when
$customer : Customer( age > 60 )
then
modify($customer) { setDiscount( 0.1 ) };
System.out.println("Give 10% discount to customers older than 60");
end
rule "conditional1:Give free parking to customers older than 60"
agenda-group "conditional1"
when
$customer : Customer( age > 60 )
$car : Car ( owner == $customer )
then
modify($car) { setFreeParking( true ) };
System.out.println("Give free parking to customers older than 60");
end
现在Drools提供了extends特性,也就是一个规则可以继承另外一个规则,并获得其约束条件。改写之后执行效果相同,代码如下:
package com.rules.conditional
import com.secbro.drools.model.Customer;
import com.secbro.drools.model.Car;
rule "conditional2:Give 10% discount to customers older than 60"
agenda-group "conditional2"
when
$customer : Customer( age > 60 )
then
modify($customer) { setDiscount( 0.1 ) };
System.out.println("conditional2:Give 10% discount to customers older than 60");
end
rule "conditional2:Give free parking to customers older than 60"
extends "conditional2:Give 10% discount to customers older than 60"
agenda-group "conditional2"
when
$car : Car ( owner == $customer )
then
modify($car) { setFreeParking( true ) };
System.out.println("conditional2:Give free parking to customers older than 60");
end
我们可以看到上面使用了extends,后面紧跟的是另外一条规则的名称。这样,第二条规则同时拥有了第一条规则的约束条件。只需要单独写此条规则自身额外需要的约束条件即可。那么,现在是否是最优的写法吗?当然不是,还可以将两条规则合并成一条来规则。这就用到了do和标记。
package com.rules.conditional
import com.secbro.drools.model.Customer;
import com.secbro.drools.model.Car;
rule "conditional3:Give 10% discount to customers older than 60"
agenda-group "conditional3"
when
$customer : Customer( age > 60 )
do[giveDiscount]
$car : Car(owner == $customer)
then
modify($car) { setFreeParking(true) };
System.out.println("conditional3:Give free parking to customers older than 60");
then[giveDiscount]
modify($customer){
setDiscount(0.1)
};
System.out.println("conditional3:Give 10% discount to customers older than 60");
end
在then中标记了giveDiscount处理操作,在when中用do来调用标记的操作。这样也当第一个约束条件判断完成之后,就执行标记giveDiscount中的操作,然后继续执行Car的约束判断,通过之后执行默认的操作。
在then中还可以添加一些判断来执行标记的操作,这样就不必每次都执行do操作,而是每当满足if条件之后才执行:
package com.rules.conditional
import com.secbro.drools.model.Customer;
import com.secbro.drools.model.Car;
rule "conditional4:Give 10% discount to customers older than 60"
agenda-group "conditional4"
when
$customer : Customer( age > 60 )
if(type == "Golden") do[giveDiscount]
$car : Car(owner == $customer)
then
modify($car) { setFreeParking(true) };
System.out.println("conditional4:Give free parking to customers older than 60");
then[giveDiscount]
modify($customer){
setDiscount(0.1)
};
System.out.println("conditional4:Give 10% discount to customers older than 60");
end
同时,还可以通过break来中断后续的判断。
package com.rules.conditional
import com.secbro.drools.model.Customer;
import com.secbro.drools.model.Car;
rule "conditional5:Give 10% discount to customers older than 60"
agenda-group "conditional5"
when
$customer : Customer( age > 60 )
if(type == "Golden") do[giveDiscount10]
else if (type == "Silver") break[giveDiscount5]
$car : Car(owner == $customer)
then
modify($car) { setFreeParking(true) };
System.out.println("conditional5:Give free parking to customers older than 60");
then[giveDiscount10]
modify($customer){
setDiscount(0.1)
};
System.out.println("giveDiscount10:Give 10% discount to customers older than 60");
then[giveDiscount5]
modify($customer){
setDiscount(0.05)
};
System.out.println("giveDiscount5:Give 10% discount to customers older than 60");
end
以上规则的执行测试代码如下,执行结果可自行尝试,源代码已经存放在GitHub:https://github.com/secbr/drools。
后语
此系列课程持续更新中,QQ群:593177274(可扫描左上侧栏目二维码),欢迎大家加入讨论。点击链接关注《Drools博客专栏》。由于Drools资料较少,教程编写不易,每篇博客都亲身实践编写demo。如果对你有帮助也欢迎赞赏(微信)! 也是对原创的最大支持!