输入从键盘到文本文件在c??代码编译但是*EOF*不工作?

#include <stdio.h>
int main ()
{
  FILE * pFile;
  char ch;
  pFile = fopen ("G:\\ IJLAL.txt","w+");
  while((ch = getchar())!=EOF)
    putc(ch,pFile);
  fclose(pFile);
  return 0;
}

can you specify the problem??? I am totally new to fopen function. and please help me with this thing

你能指出这个问题吗???我对fopen函数完全陌生。请帮我做这件事。

3 个解决方案

#1

The getchar() function returns an int value, not a char. By forcing it into a char variable, you are making it impossible to detect the EOF.

函数的作用是:返回一个int值，而不是char。通过将其强制转换为char变量，就无法检测到EOF。

Just change char ch to int ch and it will work fine.*

只要把焦炭换成整型就行了。

Actually, you will probably still have problems with the file name. Are you sure it should contain a space? And are you aware that \\ is encoded as a single backslash character?
实际上，您可能仍然会遇到文件名的问题。你确定它应该包含一个空间吗?您是否知道\\被编码为一个反斜杠字符?

#2

According to the C99 standard (7.19.1.3):

根据C99标准(7.19.1.3):

EOF which expands to an integer constant expression, with type int and a negative value, that is returned by several functions to indicate end-of-file, that is, no more input from a stream;

EOF扩展到一个整数常量表达式，带有类型int和一个负值，由多个函数返回来表示文件结束，即不再从流中输入;

The point is that EOF is out of the range of unsigned char. I am sure this was done intentionally so that all 256 basic and extended ASCII characters can still be returned, and are distinct from EOF

关键是，EOF不在无符号字符的范围内。我确信这是故意的，这样所有256个基本和扩展的ASCII字符仍然可以返回，并且与EOF不同。

#3

You can try this.

你可以试试这个。

1 - Check fopen() return values -> print errno value (perror)

1 -检查fopen()返回值->打印errno值(perror)

#include <stdio.h>
#include <stdbool.h>

int main(void)
{
    int     c;
    bool    run;
    FILE    *fd;

    run = true;
    fd = fopen("/tmp/file.txt", "w+");
    if (fd == NULL)
    {
        perror("fopen");
        return (1);
    }
    while (run == true)
    {
        c = getchar(); // Press ctrl + D for exit
        run = (!feof(stdin) && !ferror(stdin));
        if (run == true)
            putc(c, fd);
    }
    fclose(fd);
}

And if you want you can see this link.

如果你希望你能看到这个链接。

#1