在Matlab中将函数作为参数传递

时间:2022-07-24 16:04:38

I'm trying to write a function that is gets two arrays and the name of another function as arguments.

我正在尝试编写一个函数,它获取两个数组,另一个函数的名称作为参数。

e.g.

例如

main.m:

    x=[0 0.2 0.4 0.6 0.8 1.0];
    y=[0 0.2 0.4 0.6 0.8 1.0];

    func2(x,y,'func2eq')

func 2.m :
    function t =func2(x, y, z, 'func')   //"unexpected matlab expression" error message here    
    t= func(x,y,z);

func2eq.m:  
    function z= func2eq(x,y)

    z= x + sin(pi * x)* exp(y);

Matlab tells gives me the above error message. I've never passed a function name as an argument before. Where am I going wrong?

Matlab告诉我上面的错误信息。我之前从未传递过函数名作为参数。我哪里错了?

2 个解决方案

#1


35  

You could also use function handles rather than strings, like so:

你也可以使用函数句柄而不是字符串,如下所示:

main.m:

main.m文件:

...
func2(x, y, @func2eq); % The "@" operator creates a "function handle"

This simplifies func2.m:

这简化了func2.m:

function t = func2(x, y, fcnHandle)
    t = fcnHandle(x, y);
end

For more info, see the documentation on function handles

有关更多信息,请参阅有关函数句柄的文档

#2


9  

You could try in func2.m:

你可以试试func2.m:

function t = func2(x, y, funcName)  % no quotes around funcName
    func = str2func(funcName)
    t = func(x, y)
end

#1


35  

You could also use function handles rather than strings, like so:

你也可以使用函数句柄而不是字符串,如下所示:

main.m:

main.m文件:

...
func2(x, y, @func2eq); % The "@" operator creates a "function handle"

This simplifies func2.m:

这简化了func2.m:

function t = func2(x, y, fcnHandle)
    t = fcnHandle(x, y);
end

For more info, see the documentation on function handles

有关更多信息,请参阅有关函数句柄的文档

#2


9  

You could try in func2.m:

你可以试试func2.m:

function t = func2(x, y, funcName)  % no quotes around funcName
    func = str2func(funcName)
    t = func(x, y)
end