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- Test whether string is a valid integer 11 answers
测试字符串是否为有效整数11个答案
I wrote a bash script which takes numbers for calculation via user input. The problem I have is if the user types a letter or a space by mistake, the whole script fails and the user must start again.
我写了一个bash脚本,它通过用户输入获取计算数字。我遇到的问题是如果用户错误地输入了字母或空格,整个脚本都会失败,用户必须重新开始。
There must be an easy way to check the input is numeric only that will ask for the input again if anything else is input accidentally?
必须有一个简单的方法来检查输入是否只是数字,如果意外输入任何其他内容,将再次请求输入?
3 个解决方案
#1
Use a while loop
使用while循环
number=""
while [[ ! $number =~ ^[0-9]+$ ]]; do
echo Please enter your age
read number
done
echo You are $number years old
#2
And to avoid the heavy regex engine, use a simple glob:
要避免繁重的正则表达式引擎,请使用简单的glob:
if [[ ! $input || $input = *[^0-9]* ]]; then
echo "Error: '$input' is not a number." >&2
fi
#3
Allows space before and after the number, _33, or 33___ , but not 3__3. and no letters. 0 or
允许在数字_33或33___之前和之后留出空格,但不允许空间为3__3。而且没有信件。 0或
-- Get input from user until Correct
# -- get input until Correct
unset get_num
while [[ ! ${get_num} =~ ^[0-9]+$ ]]; do
echo "Please enter in a number:"
read get_num
done
echo This is a number : ${get_num}
-- Get input until Correct (within range)
# -- get input until Correct (within range)
unset get_num
while [[ ! ${get_num} =~ ^[0-9]+$ ]]; do
echo "Please enter in a number within range of (1-30):"
read get_num
! [[ ${get_num} -ge 1 && ${get_num} -le 30 ]] && unset get_num
done
echo This is a number withn a range : ${get_num}
-- get input until Correct (within range) (full regex way)
"Since regular expressions deal with text rather than with numbers, matching a number in a given range takes a little extra care. You can't just write [0-255] to match a number between 0 and 255. Though a valid regex, it matches something entirely different. [0-255] is a character class with three elements: the character range 0-2, the character 5 and the character 5 (again). This character class matches a single digit 0, 1, 2 or 5, just like [0125]." ~ http://www.regular-expressions.info/numericranges.html
“由于正则表达式处理文本而不是数字,因此匹配给定范围内的数字需要额外注意。您不能只写[0-255]来匹配0到255之间的数字。虽然是有效的正则表达式,它匹配完全不同的东西。[0-255]是一个有三个元素的字符类:字符范围0-2,字符5和字符5(再次)。这个字符类匹配单个数字0,1,2或5,就像[0125]。“ ~http://www.regular-expressions.info/numericranges.html
# -- get input until Correct (within range) (another way)
unset get_num
while [[ ! ${get_num} =~ ^([1-9]|1[0-9]|2[0-9]|30)$ ]]; do
echo "Please enter in a number within range of (1-30):"
read get_num
done
echo This is a number withn a range : ${get_num}
-- Get input, and check it only (no while loop)
# -- get input, and check it only (no while loop)
unset get_num
echo "Please enter in a number:"
read get_num
if [[ ! ${get_num} =~ ^[0-9]+$ ]] ;then
echo "${get_num} isn't a number"
else
echo "${get_num} is a number"
fi
#1
Use a while loop
使用while循环
number=""
while [[ ! $number =~ ^[0-9]+$ ]]; do
echo Please enter your age
read number
done
echo You are $number years old
#2
And to avoid the heavy regex engine, use a simple glob:
要避免繁重的正则表达式引擎,请使用简单的glob:
if [[ ! $input || $input = *[^0-9]* ]]; then
echo "Error: '$input' is not a number." >&2
fi
#3
Allows space before and after the number, _33, or 33___ , but not 3__3. and no letters. 0 or
允许在数字_33或33___之前和之后留出空格,但不允许空间为3__3。而且没有信件。 0或
-- Get input from user until Correct
# -- get input until Correct
unset get_num
while [[ ! ${get_num} =~ ^[0-9]+$ ]]; do
echo "Please enter in a number:"
read get_num
done
echo This is a number : ${get_num}
-- Get input until Correct (within range)
# -- get input until Correct (within range)
unset get_num
while [[ ! ${get_num} =~ ^[0-9]+$ ]]; do
echo "Please enter in a number within range of (1-30):"
read get_num
! [[ ${get_num} -ge 1 && ${get_num} -le 30 ]] && unset get_num
done
echo This is a number withn a range : ${get_num}
-- get input until Correct (within range) (full regex way)
"Since regular expressions deal with text rather than with numbers, matching a number in a given range takes a little extra care. You can't just write [0-255] to match a number between 0 and 255. Though a valid regex, it matches something entirely different. [0-255] is a character class with three elements: the character range 0-2, the character 5 and the character 5 (again). This character class matches a single digit 0, 1, 2 or 5, just like [0125]." ~ http://www.regular-expressions.info/numericranges.html
“由于正则表达式处理文本而不是数字,因此匹配给定范围内的数字需要额外注意。您不能只写[0-255]来匹配0到255之间的数字。虽然是有效的正则表达式,它匹配完全不同的东西。[0-255]是一个有三个元素的字符类:字符范围0-2,字符5和字符5(再次)。这个字符类匹配单个数字0,1,2或5,就像[0125]。“ ~http://www.regular-expressions.info/numericranges.html
# -- get input until Correct (within range) (another way)
unset get_num
while [[ ! ${get_num} =~ ^([1-9]|1[0-9]|2[0-9]|30)$ ]]; do
echo "Please enter in a number within range of (1-30):"
read get_num
done
echo This is a number withn a range : ${get_num}
-- Get input, and check it only (no while loop)
# -- get input, and check it only (no while loop)
unset get_num
echo "Please enter in a number:"
read get_num
if [[ ! ${get_num} =~ ^[0-9]+$ ]] ;then
echo "${get_num} isn't a number"
else
echo "${get_num} is a number"
fi