将单词(字符串)数组转换为regex，并使用它获取字符串上的匹配

What is the most concise and efficient way to translate an array of strings in a regex and then use the regex multiple times on different strings to get the result matches and then iterate over them? Now I'm using the following:

翻译regex中的字符串数组，然后在不同的字符串上多次使用regex以获得结果匹配，然后对它们进行迭代，最简洁、有效的方法是什么?现在我用的是:

var myArray = ['peaches', 'bananas', 'papaya', 'supercity'];
var myString = 'I want some papaya and some peaches';

var regexFromMyArray = new RegExp(myArray.toString().replace(/,/g, '|'), 'gi');

var matches = myString.match(regexFromMyArray) || [];

if (matches.length) {
  for (var i = 0, l = matches.length; i < l; i++) {
    console.log('Found: ' + matches[i]);
  }
}

performance is important here, so plain javascript please.

性能在这里很重要，所以请使用普通的javascript。

1 个解决方案

#1

Just join with pipeline, using Array.join

只需使用Array.join加入管道

var regexFromMyArray = new RegExp(myArray.join("|"), 'gi');

and just do this as if condition is just redundant.

如果条件是冗余的就这么做。

for(var i = 0; i < matches.length; i++)
   console.log("Found:", matches[i]);

A single method is being used instead of initial 3. (toString internally calls join(",")) and replace function is also not used.
一个方法被使用而不是初始的3。(toString内部调用join(“，”))和替换函数也不被使用。
We have removed an unnecessary if-condition. So that's pretty quick.
我们已经排除了不必要的假设条件。这是非常快速。

And since you talk about regexes, I'd like to say that

既然你谈到了regex，我想说一下。

A single regex initialization isn't going to cost you much.
一个单一的regex初始化不会花费太多。
If your objective is really to match the words in the array, then just go with String.indexOf, which is a non-regex form of solving the same.
如果你的目标是匹配数组中的单词，那么就使用字符串。indexOf，这是一种非正则表达式的解决方法。

#1