逐行读取文件并将其存储到数组中不起作用

What I want to do here is to read a text file containing phone numbers. For example:

我想在这里做的是阅读包含电话号码的文本文件。例如：

01011112222
01027413565
01022223333

I want to store these phone numbers into an array for later use. Here below is my code:

我想将这些电话号码存储到一个阵列*以后使用。以下是我的代码：

#include <stdio.h>
#include <stdlib.h>
int main(){
   FILE *fl = NULL;
   char* phoneNums[10];

   int i = 0;
   fl = fopen("phoneNum.txt", "r");

   if(fl != NULL){
      char strTemp[14];

      while( !feof(fl) ){
        phoneNums[i] = fgets(strTemp, sizeof(strTemp), fl); 
        i++;
      }
      fclose(fl);
   }
   else{
      printf("File does not exist");
   }

   return 0;
}

The problem is that whenever fgets is called, it returns the same reference of strTemp.

问题是每当调用fgets时，它都会返回strTemp的相同引用。

So every time it goes through the loop, it changes all value to the recent value in phoneNums array.

因此，每次循环时，它都会将所有值更改为phoneNums数组中的最新值。

I tried to declare char strTemp[14] inside the while loop, but it didn't work.

我试图在while循环中声明char strTemp [14]，但它不起作用。

At this point, what could I try to solve this issue?

在这一点上，我可以尝试解决这个问题？

Thanks.

谢谢。

2 个解决方案

#1

Do the below changes to get the exact result.

执行以下更改以获得准确的结果。

Change the strTemp variable to pointer variable.

将strTemp变量更改为指针变量。

 char *strTemp;

Inside while allocate the dynamic memory for the variable.

在内部同时为变量分配动态内存。

 strTemp=malloc(14);
 phoneNums[i]=fgets(strTemp,14,fl);

If you do like this it will create a new memory for each time so the value is stored in the different location. So it can't overwrite in the same location.

如果您喜欢这样，它将每次创建一个新的内存，以便将值存储在不同的位置。所以它不能在同一个位置覆盖。

#2

Hope this will help you

希望对你有帮助

#include <stdio.h>
#include<string.h>
#include <stdlib.h>
int main(){
    FILE *fl = NULL;
    char    phoneNums[3][14]; // you didn't allocate memory here. i am using static memory(for 3 phone numbers)
    int i = 0,j;
    fl = fopen("phoneNum.txt", "r");

    if(fl != NULL){
            char strTemp[14];

            while( fgets(strTemp, sizeof(strTemp), fl) ){
                    strcpy(phoneNums[i],strTemp); // you need to string copy function to copy one string to another string
                    i++;
            }
            fclose(fl);
    }
    else{
            printf("File does not exist");
    }
    for(j=0;j<i;j++) // i am printing the array content
            printf("%s\n",phoneNums[j]);

    return 0;
}

Here the dynamic allocation of memory for char *phoneNums[14];

这里为char * phoneNums动态分配内存[14];

pnoneNums=(char **)malloc(14*n); // where n is the numbers of phone numbers

#1