How to assign the result of a query to a variable in PL/pgSQL, the procedural language of PostgreSQL?
如何将查询结果分配给PL/pgSQL (PostgreSQL的过程语言)中的变量?
I have a function:
我有一个函数:
CREATE OR REPLACE FUNCTION test(x numeric)
RETURNS character varying AS
$BODY$
DECLARE
name character varying(255);
begin
name ='SELECT name FROM test_table where id='||x;
if(name='test')then
--do somthing
else
--do the else part
end if;
end;
return -- return my process result here
$BODY$
LANGUAGE plpgsql VOLATILE
In the above function I need to store the result of this query:
在上面的函数中,我需要存储这个查询的结果:
'SELECT name FROM test_table where id='||x;
to the variable name
.
变量名。
How to process this?
如何处理这个问题?
4 个解决方案
#1
97
I think you're looking for SELECT INTO
:
我认为你在寻找SELECT INTO:
select test_table.name into name from test_table where id = x;
That will pull the name
from test_table
where id
is your function's argument and leave it in the name
variable. Don't leave out the table name prefix on test_table.name
or you'll get complaints about an ambiguous reference.
这将从test_table中提取名称,其中id是函数的参数,并将其保留在name变量中。不要在test_table.name中省略表名前缀,否则您会收到关于不明确引用的抱怨。
#2
39
As long as you are assigning a single variable, you can also use plain assignment in a plpgsql function:
只要您在分配单个变量,您还可以在plpgsql函数中使用纯赋值:
name := (SELECT t.name from test_table t where t.id = x);
Or use SELECT INTO
like @mu already provided.
或者使用SELECT INTO,如@mu已经提供。
This works, too:
这是:
name := t.name from test_table t where t.id = x;
But better use one of the first two, clearer methods, as @Pavel commented.
但是最好使用前两种更清晰的方法之一,正如@Pavel评论的那样。
I shortened the syntax with a table alias additionally.
Update: I removed my code example and suggest to use IF EXISTS()
instead like provided by @Pavel.
我还用表别名缩短了语法。更新:我删除了我的代码示例,并建议使用IF exist(),如@Pavel所提供的那样。
#3
14
The usual pattern is EXISTS(subselect)
:
通常的模式是存在的(subselect):
BEGIN
IF EXISTS(SELECT name
FROM test_table t
WHERE t.id = x
AND t.name = 'test')
THEN
---
ELSE
---
END IF;
This pattern is used in PL/SQL, PL/pgSQL, SQL/PSM, ...
该模式用于PL/SQL、PL/pgSQL、SQL/PSM、……
#4
1
Create Learning Table:
创建学习表:
CREATE TABLE "public"."learning" (
"api_id" int4 DEFAULT nextval('share_api_api_id_seq'::regclass) NOT NULL,
"title" varchar(255) COLLATE "default"
);
Insert Data Learning Table:
学习表插入数据:
INSERT INTO "public"."learning" VALUES ('1', 'Google AI-01');
INSERT INTO "public"."learning" VALUES ('2', 'Google AI-02');
INSERT INTO "public"."learning" VALUES ('3', 'Google AI-01');
Step: 01
步骤:1
CREATE OR REPLACE FUNCTION get_all (pattern VARCHAR) RETURNS TABLE (
learn_id INT,
learn_title VARCHAR
) AS $$
BEGIN
RETURN QUERY SELECT
api_id,
title
FROM
learning
WHERE
title = pattern ;
END ; $$ LANGUAGE 'plpgsql';
Step: 02
一步:02
SELECT * FROM get_all('Google AI-01');
Step: 03
一步:03
DROP FUNCTION get_all();
演示:
#1
97
I think you're looking for SELECT INTO
:
我认为你在寻找SELECT INTO:
select test_table.name into name from test_table where id = x;
That will pull the name
from test_table
where id
is your function's argument and leave it in the name
variable. Don't leave out the table name prefix on test_table.name
or you'll get complaints about an ambiguous reference.
这将从test_table中提取名称,其中id是函数的参数,并将其保留在name变量中。不要在test_table.name中省略表名前缀,否则您会收到关于不明确引用的抱怨。
#2
39
As long as you are assigning a single variable, you can also use plain assignment in a plpgsql function:
只要您在分配单个变量,您还可以在plpgsql函数中使用纯赋值:
name := (SELECT t.name from test_table t where t.id = x);
Or use SELECT INTO
like @mu already provided.
或者使用SELECT INTO,如@mu已经提供。
This works, too:
这是:
name := t.name from test_table t where t.id = x;
But better use one of the first two, clearer methods, as @Pavel commented.
但是最好使用前两种更清晰的方法之一,正如@Pavel评论的那样。
I shortened the syntax with a table alias additionally.
Update: I removed my code example and suggest to use IF EXISTS()
instead like provided by @Pavel.
我还用表别名缩短了语法。更新:我删除了我的代码示例,并建议使用IF exist(),如@Pavel所提供的那样。
#3
14
The usual pattern is EXISTS(subselect)
:
通常的模式是存在的(subselect):
BEGIN
IF EXISTS(SELECT name
FROM test_table t
WHERE t.id = x
AND t.name = 'test')
THEN
---
ELSE
---
END IF;
This pattern is used in PL/SQL, PL/pgSQL, SQL/PSM, ...
该模式用于PL/SQL、PL/pgSQL、SQL/PSM、……
#4
1
Create Learning Table:
创建学习表:
CREATE TABLE "public"."learning" (
"api_id" int4 DEFAULT nextval('share_api_api_id_seq'::regclass) NOT NULL,
"title" varchar(255) COLLATE "default"
);
Insert Data Learning Table:
学习表插入数据:
INSERT INTO "public"."learning" VALUES ('1', 'Google AI-01');
INSERT INTO "public"."learning" VALUES ('2', 'Google AI-02');
INSERT INTO "public"."learning" VALUES ('3', 'Google AI-01');
Step: 01
步骤:1
CREATE OR REPLACE FUNCTION get_all (pattern VARCHAR) RETURNS TABLE (
learn_id INT,
learn_title VARCHAR
) AS $$
BEGIN
RETURN QUERY SELECT
api_id,
title
FROM
learning
WHERE
title = pattern ;
END ; $$ LANGUAGE 'plpgsql';
Step: 02
一步:02
SELECT * FROM get_all('Google AI-01');
Step: 03
一步:03
DROP FUNCTION get_all();
演示: