I'm trying to convert the output of a command like echo -e "a b\nc\nd e" to an array.
我正在尝试将echo -e“a b \ nc \ nd e”等命令的输出转换为数组。
X=( $(echo -e "a b\nc\nd e") )
Splits the input for every new line and whitespace character:
拆分每个新行和空白字符的输入：
$ echo ${#X[@]}
> 5
for i in ${X[@]} ; do echo $i ; done
a
b
c
d
e
The result should be:
结果应该是：
for i in ${X[@]} ; do echo $i ; done
a b
c
d e
2 个解决方案
#1
13
You need to change your Internal Field Separator variable (IFS) to a newline first.
您需要先将内部字段分隔符变量（IFS）更改为换行符。
$ IFS=$'\n'; arr=( $(echo -e "a b\nc\nd e") ); for i in ${arr[@]} ; do echo $i ; done
a b
c
d e
#2
0
Set the IFS to newline. By default, it is space.
将IFS设置为换行符。默认情况下，它是空间。
[jaypal:~] while IFS=$'\n' read -a arry; do
echo ${arry[0]};
done < <(echo -e "a b\nc\nd e")
a b
c
d e
#1
13
You need to change your Internal Field Separator variable (IFS) to a newline first.
您需要先将内部字段分隔符变量（IFS）更改为换行符。
$ IFS=$'\n'; arr=( $(echo -e "a b\nc\nd e") ); for i in ${arr[@]} ; do echo $i ; done
a b
c
d e
#2
0
Set the IFS to newline. By default, it is space.
将IFS设置为换行符。默认情况下，它是空间。
[jaypal:~] while IFS=$'\n' read -a arry; do
echo ${arry[0]};
done < <(echo -e "a b\nc\nd e")
a b
c
d e