获取除第一个之外的bash数组的所有元素

时间:2021-12-02 15:41:13

I have an indexed bash array and I'd like to use an expression like "${a[@]}" except I want it to not include a[0]. The best that I can think of is this:

我有一个索引的bash数组,我想使用像“$ {a [@]}”这样的表达式,除非我希望它不包含[0]。我能想到的最好的是:

j=0
for i in "${a[@]}"
do
    b[j]=${a[++j]}
done

and then use "${b[@]}". Is there a better way?

然后使用“$ {b [@]}”。有没有更好的办法?

1 个解决方案

#1


33  

$ a=(1 2 3)
$ echo "${a[@]:1}"
2 3

#1


33  

$ a=(1 2 3)
$ echo "${a[@]:1}"
2 3