I need a way to match file names in directory.
我需要一种方法来匹配目录中的文件名。
For example I have three files:
例如,我有三个文件:
CAt_DoG_ZebRa.TXT
MOUSE_lion_deer_BIRD.TXT
fIsh_biRD_LION.TXT
I am not regex expert by any means, however I've used something like this in SnapLogic and Pentaho before:
我不是任何正则表达式专家,但我之前在SnapLogic和Pentaho中使用过类似的东西:
(?i).*(?=.*bird)(?=.*lion).*.TXT
The above would match all file names that contain the words 'bird' and 'lion' with case being ignored and the order of the words would not matter. Very powerful! So it would match these two:
上面的内容将匹配包含单词'bird'和'lion'的所有文件名,其中case被忽略,单词的顺序无关紧要。很强大!所以它会匹配这两个:
MOUSE_lion_deer_BIRD.TXT
fIsh_biRD_LION.TXT
I tried lots of variations of the above in conjunction with find and grep to no avail. For example:
我尝试了上面的许多变化与find和grep一起无济于事。例如:
find . -regex ".*/(?i).*(?=.*bird)(?=.*lion).*.TXT"
The above find does not match anything.
以上查找与任何内容都不匹配。
Can anyone recommend a way to do this?
谁能推荐一种方法来做到这一点?
3 个解决方案
#1
2
# ls
asdafsdfdBirdasfdfd.txt dasdbirdbfdgdlionb.txt fgdfLionqweBirdaqw.txt
# ls | /usr/gnu/bin/grep -i -E '.*(bird.*lion|lion.*bird).*\.txt'
dasdbirdbfdgdlionb.txt
fgdfLionqweBirdaqw.txt
a trick: when you writing some regular expression using look ahead or look behind, doubt it, and either change another way to write it or think about whether regular expression is a suitable tool for this problem.
一个技巧:当你使用向前看或者向后看时写一些正则表达式,怀疑它,要么改变另一种方式来编写它,要么考虑正则表达式是否适合这个问题的工具。
#2
7
shopt -s globstar # enable recursive globs
shopt -s nocaseglob # make globs case-insensitive
for file in ./**/*bird*lion*.txt; do
echo "found: $file"
done
...or, if you didn't care about order between those words:
......或者,如果你不关心这些词之间的顺序:
shopt -s globstar # enable recursive globs
shopt -s nocaseglob # make globs case-insensitive
shopt -s extglob # enable extended globbing syntax
for file in ./**/*@(bird*lion|lion*bird)*.txt; do
echo "found: $file"
done
#3
0
First, find doesn't support PCRE regex engine, so this a solution for your problem, with perl and bash (recursive) :
首先,find不支持PCRE正则表达式引擎,所以这是一个解决你的问题的方法,使用perl和bash(递归):
bash -c "shopt -s globstar; perl -lne 'print if /i.*bird/i and /i.*lion/i' **"
This solution work with all filenames matching bird and lion, in any orders
此解决方案适用于所有与鸟和狮子匹配的文件名,以任何顺序
#1
2
# ls
asdafsdfdBirdasfdfd.txt dasdbirdbfdgdlionb.txt fgdfLionqweBirdaqw.txt
# ls | /usr/gnu/bin/grep -i -E '.*(bird.*lion|lion.*bird).*\.txt'
dasdbirdbfdgdlionb.txt
fgdfLionqweBirdaqw.txt
a trick: when you writing some regular expression using look ahead or look behind, doubt it, and either change another way to write it or think about whether regular expression is a suitable tool for this problem.
一个技巧:当你使用向前看或者向后看时写一些正则表达式,怀疑它,要么改变另一种方式来编写它,要么考虑正则表达式是否适合这个问题的工具。
#2
7
shopt -s globstar # enable recursive globs
shopt -s nocaseglob # make globs case-insensitive
for file in ./**/*bird*lion*.txt; do
echo "found: $file"
done
...or, if you didn't care about order between those words:
......或者,如果你不关心这些词之间的顺序:
shopt -s globstar # enable recursive globs
shopt -s nocaseglob # make globs case-insensitive
shopt -s extglob # enable extended globbing syntax
for file in ./**/*@(bird*lion|lion*bird)*.txt; do
echo "found: $file"
done
#3
0
First, find doesn't support PCRE regex engine, so this a solution for your problem, with perl and bash (recursive) :
首先,find不支持PCRE正则表达式引擎,所以这是一个解决你的问题的方法,使用perl和bash(递归):
bash -c "shopt -s globstar; perl -lne 'print if /i.*bird/i and /i.*lion/i' **"
This solution work with all filenames matching bird and lion, in any orders
此解决方案适用于所有与鸟和狮子匹配的文件名,以任何顺序