使用sed匹配一个模式，并从行删除到文件的末尾

I'm trying to match a pattern from piped input and/or a file, and then remove from the matched lines to the end of the file, inclusive. I've looked everywhere, but can't seem to find an expression that would fit my needs.

我正在尝试从管道输入和/或文件中匹配一个模式，然后从匹配的行中删除到文件的末尾，包括。我到处都找遍了，但似乎找不到一个符合我需求的表达。

The following expression allows me to remove to the beginning of the stream, including the matched pattern:

下面的表达式允许我移到流的开头，包括匹配的模式:

sed -e '1,/Files:/d'

Given some sample data:

给出一些示例数据:

Blah blah blah
Foobar foo foo
Files:
 somefiles.tar.gz 1 2 3
 somefiles.tar.gz 1 2 3

-----THIS STUFF IS USELESS-----
BLEH BLEH BLEH
BLEH BLEH BLEH

Running the above expression produces:

运行上述表达式将产生:

Files:
 somefiles.tar.gz 1 2 3
 somefiles.tar.gz 1 2 3

-----THIS STUFF IS USELESS-----
BLEH BLEH BLEH
BLEH BLEH BLEH

I would like to achieve a similar effect, but in the opposite direction. Using the output from the previous expression, I want to remove from -----THIS STUFF IS USELESS----- to the end of the file, inclusive. It should produce (after going through the first expression):

我想达到类似的效果，但方向相反。它应该产生(经过第一个表达式后):

Files:
 somefiles.tar.gz 1 2 3
 somefiles.tar.gz 1 2 3

I'm also open to using any other tools, as long as it is available on any other POSIX system and does not use version specific (e.g. GNU-specific) options.

我还可以使用任何其他的工具，只要它可以在任何其他POSIX系统上使用，并且不使用特定于版本的(例如特定于gnui的)选项。

The actual text can be found here: http://pastebin.com/CYBbJ3qr Note the change from -----THIS STUFF IS USELESS----- to -----BEGIN PGP SIGNATURE-----.

实际的文本可以在这里找到:http://pastebin.com/CYBbJ3qr注意从---这个东西是没用的----- --开始PGP签名-----。

5 个解决方案

#1

why not

为什么不

 sed '/^-----THIS STUFF IS USELESS-----$/,$d' file

In a range expression like you have used, ',$' will specify "to the end of the file"

在您使用的范围表达式中，'，$'将指定“文件的末尾”

1 is first line in file, 
$ is last line in file.

output

输出

Files:
 somefiles.tar.gz 1 2 3
 somefiles.tar.gz 1 2 3

IHTH

#2

sed -e '/^-----THIS STUFF IS USELESS-----$/,$ d'

#3

Instead of trying to figure out how to express what what you don't want, just print what you DO want:

与其试着去表达你不想要的东西，不如把你想要的打印出来:

awk -v RS= '/Files:/' file

EDIT: Given your modified input:

编辑:给定您修改后的输入:

awk '/^Files:$/{f=1} f; /^$/{f=0}' file

or:

或者:

awk '/^Files:$/{f=1} f; /^-----THIS STUFF IS USELESS-----$/{f=0}' file

if you prefer.

如果你喜欢。

You can also use either of these:

你也可以使用以下任何一种:

awk '/^Files:$/,/^-----THIS STUFF IS USELESS-----$/' file
sed '/^Files:$/,/^-----THIS STUFF IS USELESS-----$/' file

but they are hard to extend later.

但以后很难再延伸。

#4

Dirty utility knife grep version:

肮脏实用刀grep版本:

cat your_output.txt | grep -B 99999999 "THIS STUFF IS USELESS" | grep -v "THIS STUFF IS USELESS"

#5

Here's a regular expression that I think will do what you want it to: ^(?:(?!Files:).)+|\s*-----THIS STUFF IS USELESS-----.+ Make sure to set the dotall flag.

这是一个正则表达式,我认为会做你想要的:^(?:? !文件:。)+ | \ s * - - - - - - - - - - - -这东西是无用的。+务必设置dotall旗帜。

Demo+explanation: http://regex101.com/r/xF2fN5

演示+解释:http://regex101.com/r/xF2fN5

You only need to run this one expression.

只需要运行这个表达式。

#1