Write a function that reverses a string. The input string is given as an array of characters char[].
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
You may assume all the characters consist of printable ascii characters.
Example 1:
Input: ["h","e","l","l","o"]
Output: ["o","l","l","e","h"]
Example 2:
Input: ["H","a","n","n","a","h"]
Output: ["h","a","n","n","a","H"]
这道题没什么难度，直接从两头往中间走，同时交换两边的字符即可，参见代码如下：
解法一：
class Solution {
public:
void reverseString(vector<char>& s) {
int left = , right = (int)s.size() - ;
while (left < right) {
char t = s[left];
s[left++] = s[right];
s[right--] = t;
}
}
};
我们也可以用 swap 函数来帮助我们翻转：
解法二：
class Solution {
public:
void reverseString(vector<char>& s) {
int left = , right = (int)s.size() - ;
while (left < right) {
swap(s[left++], s[right--]);
}
}
};
Github 同步地址：
https://github.com/grandyang/leetcode/issues/344
类似题目：
参考资料：
https://leetcode.com/problems/reverse-string/
https://leetcode.com/problems/reverse-string/discuss/80935/Simple-C%2B%2B-solution