Servlet--取得session,application内置对象

时间:2022-09-03 15:22:48



在前面的博客里面,使用Servlet取得了request,response,config对象,实际上通过Servlet程序也可以取得session,application等内置对象。





1,通过HttpServletRequest取得HttpSession

<span style="white-space:pre">	</span>//返回当前的session
public abstract HttpSession getSession();
//返回当前的session,如果没有则创建一个新的session对象返回
public abstract HttpSession getSession(boolean paramBoolean);
package linkin;

import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession; public class LinkinServlet extends HttpServlet
{
private static final long serialVersionUID = 1L; @Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException
{
HttpSession session = req.getSession();
System.out.println(session.getId());//4214F4CE399E02730C3219CF0BD83623
session.setAttribute("age", 25);
System.out.println(session.getAttribute("age"));//25 } @Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException
{
this.doGet(req, resp);
} }
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <servlet>
<servlet-name>LinkinServlet</servlet-name>
<servlet-class>linkin.LinkinServlet</servlet-class>
<init-param>
<param-name>name</param-name>
<param-value>LinkinPark...</param-value>
</init-param>
</servlet> <servlet-mapping>
<servlet-name>LinkinServlet</servlet-name>
<url-pattern>/LinkinServlet</url-pattern>
</servlet-mapping> </web-app>

2,利用GenericServlet取得ServletContext实例

public ServletContext getServletContext()
{
return getServletConfig().getServletContext();
}
package linkin;

import java.io.IOException;

import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse; public class LinkinServlet extends HttpServlet
{
private static final long serialVersionUID = 1L; @Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException
{
ServletContext context = getServletContext();
//获取“/”,也就是项目实际在服务器上物理位置
System.out.println(context.getRealPath("/"));//E:\Workserver\apache-tomcat-6.0.37\webapps\linkin\ } @Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException
{
this.doGet(req, resp);
} }
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <servlet>
<servlet-name>LinkinServlet</servlet-name>
<servlet-class>linkin.LinkinServlet</servlet-class>
<init-param>
<param-name>name</param-name>
<param-value>LinkinPark...</param-value>
</init-param>
</servlet> <servlet-mapping>
<servlet-name>LinkinServlet</servlet-name>
<url-pattern>/LinkinServlet</url-pattern>
</servlet-mapping> </web-app>