I'm following a tutorial on youtube and he said that it's needed to write some asm code in C (i'm not very good in assembly) so i just copyed the entire code:
我正在关注youtube上的一个教程,他说需要在C中编写一些asm代码(我在汇编方面不是很好)所以我只是复制了整个代码:
unsigned char inPortB (unsigned int _port) {
unsigned char rv;
__asm__ __volatile__ ("inb %1, %0" : "=a" (rv) : "dN" (_port));
return rv;
}
and
void outPortB (unsigned int _port, unsigned char _data) {
__asm__ __volatile__ ("outb %1, %0" : : "dN" (_port), "a" (_data));
}
but when i compile i get this error:
但是当我编译我得到这个错误:
operand type mismatch for 'in'
operand type mismatch for 'out'
how can i fix it?
我该怎么办呢?
1 个解决方案
#1
2
The port number needs to be in dx
which is a 16 bit register. To make gcc generate a reference to dx
instead of edx
as it does with your code, you need to give _port
a 16 bit type, e.g. unsigned short
:
端口号需要是dx,这是一个16位寄存器。要使gcc生成对dx而不是edx的引用,就像对代码一样,你需要给_port一个16位类型,例如未签名的短片:
unsigned char inPortB (unsigned short _port) {
unsigned char rv;
__asm__ __volatile__ ("inb %1, %0" : "=a" (rv) : "dN" (_port));
return rv;
}
This should fix your issues.
这应该可以解决您的问题。
#1
2
The port number needs to be in dx
which is a 16 bit register. To make gcc generate a reference to dx
instead of edx
as it does with your code, you need to give _port
a 16 bit type, e.g. unsigned short
:
端口号需要是dx,这是一个16位寄存器。要使gcc生成对dx而不是edx的引用,就像对代码一样,你需要给_port一个16位类型,例如未签名的短片:
unsigned char inPortB (unsigned short _port) {
unsigned char rv;
__asm__ __volatile__ ("inb %1, %0" : "=a" (rv) : "dN" (_port));
return rv;
}
This should fix your issues.
这应该可以解决您的问题。