通过函数传递多个但不同的变量/输入？

I would like to pass multiple different variables through one function that returns a single value/output. The only way I can think to do this is to call the function for each value that needs to pass through it.

我想通过一个返回单个值/输出的函数传递多个不同的变量。我能想到的唯一方法是为每个需要通过它的值调用函数。

eg.

例如。

int foo = 9;
int doo = 4;
int yoo = 23;
convertIntToSomethingElse(foo);
convertIntToSomethingElse(doo);
convertIntToSomethingElse(yoo);

I've got a strong feeling this is bad programming and that there is a more efficient way of doing this.

我有一种强烈的感觉，这是糟糕的编程，并且有一种更有效的方法来做到这一点。

1 个解决方案

#1

Since you asked for an example.

既然你问了一个例子。

There are 2 ways to do this:

有两种方法可以做到这一点：

First, is to pass the entire array to a function and then do things with those multiple times inside the array:

首先，是将整个数组传递给一个函数，然后在数组中多次执行这些操作：

int yourArray[3] = {9, 4, 23};
//get the number of elements in the array by dividing total size by a 
//size of a single element
//if you know the size you can just use that, but it's not reccomended

size_t n = sizeof(a)/sizeof(a[0]); //Pass this to function to get array size

void yourFunction (int a[], int sizeOfArray){

    int i;
    for(i=0;i<sizeOfArray;i++){
        //do stuff you need
    }
}

The second way is to just run the function multiple times in the array using a loop:

第二种方法是使用循环在数组中多次运行该函数：

for(i=0; i<n; i++){
    yourFunction(yourArray[i]);
}

#1