如何获取正在运行的服务器URL

When i run the server it shows me a message http://127.0.0.1:8000/. I want to get the url in code. I dont have request object there.

当我运行服务器时，它会显示一条消息http://127.0.0.1:8000/。我想在代码中获取url。我那里没有请求对象。

5 个解决方案

#1

request.build_absolute_uri('/')

or you could try

或者你可以试试

import socket
socket.gethostbyname(socket.gethostname())

#2

With Django docs here, You can use:

使用Django文档，您可以使用：

domain = request.get_host()
# domain = 'localhost:8000'

#3

If you want to know exactly the IP address that the development server is started with, you can use sys.argv for this. The Django development server uses the same trick internally to restart the development server with the same arguments

如果您想确切知道开发服务器的IP地址，可以使用sys.argv。 Django开发服务器在内部使用相同的技巧来重新启动具有相同参数的开发服务器

Start development server:

启动开发服务器：

manage.py runserver 127.0.0.1:8000

Get address in code:

在代码中获取地址：

if settings.DEBUG:
    import sys
    print sys.argv[-1]

This prints 127.0.0.1:8000

这打印127.0.0.1:8000

#4

import socket
host = socket.gethostname()

#5

import re
import subprocess


def get_ip_machine():
    process = subprocess.Popen(['ifconfig'], stdout=subprocess.PIPE)

    ip_regex = re.compile('(((1?[0-9]{1,2})|(2[0-4]\d)|(25[0-5]))\.){3}((1?[0-9]{1,2})|(2[0-4]\d)|(25[0-5]))')

    return ip_regex.search(process.stdout.read(), re.MULTILINE).group()

#1

request.build_absolute_uri('/')