头中的结构体的前向声明

I am trying to pass struct pointer in function. I have a typedef in file1.h, and want to only include that header to file2.c, because file2.h only need pointer. In C++ I would just write like I did here, but using C99 it doesn't work. If someone has any suggestions how to pass struct pointer without full definition it would be very appreciated. Compiler - gcc.

我试图在函数中传递struct指针。我在file1中有一个类型定义。h，并只想包含文件2的头。c,因为file2。h只需要指针。在c++中，我可以像这里那样写，但是用C99不行。如果有人对如何在没有完整定义的情况下传递struct指针有任何建议，我们将非常感激。编译器gcc。

file1.h

file1.h

typedef struct
{
    ...
} NEW_STRUCT;

file2.h

file2.h

struct NEW_STRUCT;

void foo(NEW_STRUCT *new_struct); //error: unknown type name 'NEW_STRUCT'

file2.c

file2.c

#include "file2.h"

#include "file1.h"

void foo(NEW_STRUCT *new_struct)
{
    ...
}

2 个解决方案

#1

I think you just have to name your structure, and do a forward declaration of it and after re typedef it.

我认为你只需要给你的结构命名，然后对它做一个前向声明，然后在重新定义它之后。

First file:

第一个文件:

 typedef struct structName {} t_structName;

Second file:

第二个文件:

  struct stuctName;
  typedef struct structName t_structName

#2

You may try this:

你可以试试这个:

file1.h

file1.h

typedef struct _NEW_STRUCT  // changed!
{
    ...
} NEW_STRUCT;

file2.h

file2.h

struct _NEW_STRUCT; // changed!

void foo(struct _NEW_STRUCT *new_struct); // changed!

file2.c

file2.c

#include "file2.h"
#include "file1.h"

void foo(NEW_STRUCT *new_struct)
{
    ...
}