如何知道头文件来自何处?

How can I tell where g++ was able to find an include file? Basically if I

我如何知道g++在哪里可以找到包含文件?基本上如果我

#include <foo.h>

g++ will scan the search path, using any include options to add or alter the path. But, at the end of days, is there a way I can tell the absolute path of foo.h that g++ chose to compile? Especially relevant if there is more than one foo.h in the myriad of search paths.

g++将扫描搜索路径，使用任何包含选项来添加或改变路径。但是，最后，有没有一种方法可以告诉我foo的绝对路径。h g++选择编译?特别是当有多个foo时。h在无数的搜索路径中。

Short of a way of accomplishing that... is there a way to get g++ to tell me what its final search path is after including defaults and all include options?

缺少实现这一点的方法……有没有办法让g++在包含默认值和所有包含选项之后告诉我它的最终搜索路径?

4 个解决方案

#1

This will give make dependencies which list absolute paths of include files:

这将使依赖项列出包含文件的绝对路径:

gcc  -M showtime.c

If you don't want the system includes (i.e. #include <something.h>) then use:

如果您不希望系统包含(例如:#include )，那么使用:

gcc  -MM showtime.c

#2

g++ -H ...

will also print the full path of include files in a format which shows which header includes which

还将打印包含文件的完整路径，以显示哪些头包含哪些头

#3

Sure use

确定使用

g++ -E -dI  ... (whatever the original command arguments were)

#4

If you use -MM or one of the related options (-M, etc), you get just the list of headers that are included without having all the other preprocessor output (which you seem to get with the suggested g++ -E -dI solution).

如果您使用-MM或其中一个相关选项(-M，等等)，您只会得到包含在其中的头信息列表，而不会得到所有其他预处理器输出(您似乎可以通过建议的g++ -E -dI解决方案获得这些信息)。

#1