如何在Ascending order android中对ArrayList 进行排序

时间:2022-05-19 15:08:03

I have a requirement to sort ArrayList<Object>(Custom objects) in Ascending order based upon name. For that purpose I am using comparator method as like

我需要根据名称按升序排序ArrayList (自定义对象)。为此我正在使用比较法

My ArrayList :

我的ArrayList:

ArrayList<Model> modelList = new ArrayList<Model>();

ArrayList modelList = new ArrayList ();

Code I am using:

我正在使用的代码:

   Comparator<Model> comparator = new Comparator<Model>() {
            @Override
            public int compare(CarsModel lhs, CarsModel rhs) {

                String  left = lhs.getName();
                String right = rhs.getName();

                return left.compareTo(right);

            }
        };

   ArrayList<Model> sortedModel = Collections.sort(modelList,comparator);

//While I try to fetch the sorted ArrayList, I am getting error message 

I am completely stuck up and really dont know how to proceed further in order to get sorted list of ArrayList<Object>. Please help me with this. Any help and solutions would be helpful for me. I am posting my exact scenario for your reference. Thanks in advance.

我完全陷入困境,真的不知道如何继续进行以获得ArrayList 的排序列表。请帮我解决一下这个。任何帮助和解决方案对我都有帮助。我发布了我的确切场景供您参考。提前致谢。

Example:

例:

ArrayList<Model> modelList = new ArrayList<Model>();
modelList.add(new Model("chandru"));
modelList.add(new Model("mani"));
modelList.add(new Model("vivek"));
modelList.add(new Model("david"));

Normal List:

正常清单:

for(Model mod : modelList){
  Log.i("names", mod.getName());
}

Output :

输出:

chandru
mani
vivek
david

My requirement after sorting to be like:

排序后我的要求如下:

for(Model mod : modelList){
  Log.i("names", mod.getName());
}

Output :

输出:

chandru
david
mani
vivek

2 个解决方案

#1


28  

Your approach was right. Make your Comparator inner like in the following example (or you can create a new class instead):

你的方法是对的。在下面的示例中使您的Comparator内部(或者您可以创建一个新类):

ArrayList<Model> modelList = new ArrayList<>();
modelList.add(new Model("chandru"));
modelList.add(new Model("mani"));
modelList.add(new Model("vivek"));
modelList.add(new Model("david"));

Collections.sort(modelList, new Comparator<Model>() {
    @Override
    public int compare(Model lhs, Model rhs) {
        return lhs.getName().compareTo(rhs.getName());
    }
});

output:

输出:

chandru
david
mani
vivek

#2


3  

 Collections.sort(actorsList, new Comparator<Actors>() {
      @Override
      public int compare(Actors lhs, Actors rhs) {
       return lhs.getName().compareTo(rhs.getName());
     }
    });

#1


28  

Your approach was right. Make your Comparator inner like in the following example (or you can create a new class instead):

你的方法是对的。在下面的示例中使您的Comparator内部(或者您可以创建一个新类):

ArrayList<Model> modelList = new ArrayList<>();
modelList.add(new Model("chandru"));
modelList.add(new Model("mani"));
modelList.add(new Model("vivek"));
modelList.add(new Model("david"));

Collections.sort(modelList, new Comparator<Model>() {
    @Override
    public int compare(Model lhs, Model rhs) {
        return lhs.getName().compareTo(rhs.getName());
    }
});

output:

输出:

chandru
david
mani
vivek

#2


3  

 Collections.sort(actorsList, new Comparator<Actors>() {
      @Override
      public int compare(Actors lhs, Actors rhs) {
       return lhs.getName().compareTo(rhs.getName());
     }
    });