如何在包含子目录的目录中找到所有的零字节文件

How can I find all zero-byte files in a directory and even in subdirectories?

如何在目录甚至子目录中找到所有的零字节文件?

I have done this:

我所做的:

#!/bin/bash
lns=`vdir -R *.* $dir| awk '{print $8"\t"$5}'`
temp=""
for file in $lns
do
  if test $file = "0"
  then
    printf $temp"\t"$file"\n"
  fi
 temp=$file
done

but I only get results in that directory file not all files and if any file name has a space then I get only first word followed by tab

但是我只在那个目录文件中得到结果而不是所有的文件，如果任何文件名都有空格，那么我只会得到第一个单词后面跟着tab

Can anyone help me?

谁能帮我吗?

4 个解决方案

#1

103

To print the names of all files in and below $dir of size 0:

打印大小为0的$dir内及以下所有文件的名称:

find "$dir" -size 0

Note that not all implementations of find will produce output by default, so you may need to do:

注意，并不是所有find的实现都默认生成输出，所以您可能需要这样做:

find "$dir" -size 0 -print

#2

As addition to the answers above:

除上述答案外:

If you would like to delete those files

如果您想删除这些文件。

find $dir -size 0 -type f -delete

#3

No, you don't have to bother grep.

不，你不必麻烦grep。

find $dir -size 0 ! -name "*.xml"

#4

This is the correct way to search for size 0:

这是搜索0码的正确方法:

find /path/to/dir -size 0 -type f -name "*.xml"

Search for multiple file extensions of size 0:

搜索多个大小为0的文件扩展名:

find /path/to/dir -size 0 -type f \( -iname \*.css -o -iname \*.js \)

Note: If you removed the $ ... $ the results would be all of the files that meet this requirement hence ignoring the size 0.

注意:如果你去掉了\(……)结果将是所有满足此要求的文件，因此忽略大小0。

#1

103