I basically want to do this:
我基本上想要这样做:
grep 'example.com' www_log > example.com.YYYY-MM-DD-H:i:S.log
...with of course the filename being example.com.2008-09-27-11:21:30.log
...当然文件名为example.com.2008-09-27-11:21:30.log
I'd then put this in crontab to run daily.
然后我将它放在crontab中以便每天运行。
3 个解决方案
#1
9
The verbose method:
详细方法:
grep 'example.com' www_log > `date +example.com.%Y-%m-%d-%H:%M:%S.log`
The terse method:
简洁的方法:
grep 'example.com' www_log > `date +example.com.%F-%T.log`
#2
5
grep 'example.com' www_log > example.com.$(date +%F-%T).log
#3
2
Here is another way, that I usually use:
这是我通常使用的另一种方式:
grep 'example.com' www_log > example.com.`date +%F-%T`.log
Backticks are a form of command substitution. Another form is to use $():
反引号是命令替换的一种形式。另一种形式是使用$():
$(command)
which is the same as:
这与:
`command`
#1
9
The verbose method:
详细方法:
grep 'example.com' www_log > `date +example.com.%Y-%m-%d-%H:%M:%S.log`
The terse method:
简洁的方法:
grep 'example.com' www_log > `date +example.com.%F-%T.log`
#2
5
grep 'example.com' www_log > example.com.$(date +%F-%T).log
#3
2
Here is another way, that I usually use:
这是我通常使用的另一种方式:
grep 'example.com' www_log > example.com.`date +%F-%T`.log
Backticks are a form of command substitution. Another form is to use $():
反引号是命令替换的一种形式。另一种形式是使用$():
$(command)
which is the same as:
这与:
`command`