如何使Ant INCLUDE文件集优先于EXCLUDE

If I have a fileset like this:

如果我有这样的文件集:

<fileset dir=".">
  <exclude name="classes/*"/>
  <include name="**/zar.class"/>   
</fileset>

The exclude takes precedence over the include and I don't end up with any classes. [since for this hypothetical example, zar.class is in the classes dir] I would like to include the zar file, even though it is in the classes dir.

排除优先于include,我不会以任何类结束。 [因为对于这个假设的例子,zar.class在类dir中]我想包含zar文件,即使它在类dir中。

I banged my head against this one for a while, reading about selectors, patternsets, filesets, trying to combine filesets, etc. but could not get it working.

我对这个问题猛烈抨击了一段时间,阅读有关选择器,模式集,文件集,尝试组合文件集等但无法使其正常工作。

Anyone know how to do this?

有人知道怎么做吗?

3 个解决方案

#1

Why do you need the exclude element ?

为什么需要exclude元素?

<fileset dir=".">
  <include name="**/zar.class"/>   
</fileset>

should give you the exact set of files you are after: zar.class, and none of the other .class files in classes/.

应该为您提供以下文件的确切集合:zar.class,以及类/中的其他.class文件。

Just put this in community wiki mode, because I am not sure, on second thought, that it is actually what you are after:
you may want everything, including classes/.../zar.class, except classes/....

只是把它放在社区维基模式中,因为我不确定,在第二个想法,它实际上是你所追求的:你可能想要一切,包括类/.../ zar.class,除了类/ ....

My solution would only give you zar.class.

我的解决方案只会给你zar.class。

Please leave a comment: if this is not a good solution, I will remove it.

请留言:如果这不是一个好的解决方案,我会将其删除。

#2

I'm not sure exactly what you want but I think you were on the right track looking at pattersets: How about:

我不确定你想要什么,但我认为你在正确的轨道上看着pattersets:怎么样:

<patternset id="a">
  <exclude name="classes/*"/>
</patternset>

<patternset id="b">
  <include name="**/zar.class"/>  
</patternset>

<fileset dir=".">
  <patternset refid="a" />
  <patternset refid="b" />
</fileset>

#3

Which version of Ant was used in the original question?

在原始问题中使用了哪个版本的Ant?

With Ant 1.8.2, the stanza does produce the desired result!?

使用Ant 1.8.2,该节确实产生了预期的结果!?

<fileset dir="." id="some.fileset">
    <exclude name="build/classes/*" />
    <include name="**/A.class" />
</fileset>

<target name="test">
    <pathconvert pathsep="${line.separator}" property="listed.fileset" refid="some.fileset"/>
    <echo message="${listed.fileset}" />
</target>

Path and name slightly different, but this does show A.class, and does not show B.class, which is right next to it.

路径和名称略有不同,但这确实显示了A.class,并且没有显示B.class,它就在它旁边。

#1