uva-141-枚举

时间:2022-07-14 14:39:20

旋转过程的下标变化,画个2x2的表格,模拟就可以出来了

#include <string>
#include<iostream>
#include<map>
#include<memory.h>
#include<vector>
#include<algorithm> namespace cc
{
using std::cout;
using std::endl;
using std::cin;
using std::map;
using std::vector;
using std::string;
using std::sort; constexpr int N = 51; map<string, int> status;
int board[N][N]; int n;
string toString(int b[][N])
{
string str = "";
for (int i=1;i<=n;i++)
{
for (int j=1;j<=n;j++)
{
str += std::to_string(b[i][j]);
}
}
return str; } string xuanzhuan(int i)
{
int temp[N][N];
if (i == 0)
{
//顺时针90度
for (int i = 1, k = n; i <= n; i++, k--)
for (int j = 1; j <= n; j++)
temp[j][k] = board[i][j];
return toString(temp);
}
else if (i==1)
{
for (int i = 1, k = n; i <= n; i++, k--)
for (int j = 1; j <= n; j++)
temp[j][k] = board[i][j];
// 180
int temp2[N][N];
for (int i = 1, k = n; i <= n; i++, k--)
for (int j = 1; j <= n; j++)
temp2[j][k] = temp[i][j];
return toString(temp2);
}
else if (i==2)
{ for (int i = 1; i <= n; i++)//逆时针90度
for (int j = 1, k = n; j <= n; j++, k--)
temp[k][i] = board[i][j];
return toString(temp);
} } void solve()
{
while (cin>>n&&n)
{
memset(board,0,sizeof(board));
status.clear();
int r, c;
char op;
int ok = 0;
int play = 1;
int step = 0;
for (int i=1;i<=2*n;i++)
{
cin >> r >> c >> op;
if (op=='-')
{
//nazou
board[r][c] = 0;
}
else
{
board[r][c] = 1;
}
if(ok==0)
{
step=i;
play = i;
string str = "";
str = xuanzhuan(0);
if (ok==0&&status[str] == 1)
{
ok = 1;
}
str = xuanzhuan(1);
if (ok == 0 && status[str] == 1)
{
ok = 1;
}
str = xuanzhuan(2);
if (ok == 0 && status[str] == 1)
{
ok = 1;
}
str = toString(board);
if (ok == 0 && status[str] == 1)
{
ok = 1;
}
status[str] = 1;
}
}
if (ok == 0)
{
cout << "Draw" << endl;
}
else
{
cout << "Player " << (play % 2+1) << " wins on move " << step << endl;
}
}
} }; int main()
{ #ifndef ONLINE_JUDGE
freopen("d://1.text", "r", stdin);
#endif // !ONLINE_JUDGE
cc::solve(); return 0;
}