用python获取当前目录的所有文件名,按文件大小排列后保存为文件

时间:2021-08-20 14:35:10
 1 # 咩咩咩咩咩咩
 2 import os
 3 import codecs
 4 
 5 #get filename and size
 6 j={}
 7 for i in os.listdir("."):
 8     m = os.path.join(".",i)
 9     if os.path.isfile(m):
10         j[i]=os.path.getsize(m)
11 
12 #sort the dictionary
13 sort_result = sorted(j.iteritems(),key = lambda asd:asd[1],reverse=False)
14 
15 #print the result
16 f = codecs.open('flist.txt','w','utf-8')
17 for k in sort_result:
18     word = k[0]+" "+str(k[1])+"\n"
19     #print word,
20     if not isinstance(word,unicode):
21         word = unicode(word,"acsii")
22     #print isinstance(word,unicode)
23     #print word,
24 
25     f.write(word)
26 f.close()

很简单~ 但是做个笔记

1 sorted

2 windows系统编码是gb2312,转utf-8需要先转unicode,再转utf-8,中文是没办法直接转换(在python2.x的情况下如此)