UTF8和GB2312的相互转换

char* G2U(const char* gb2312)
{
	int len = MultiByteToWideChar(CP_ACP, 0, gb2312, -1, NULL, 0);
	wchar_t* wstr = new wchar_t[len+1];
	memset(wstr, 0, len+1);
	MultiByteToWideChar(CP_ACP, 0, gb2312, -1, wstr, len);
	len = WideCharToMultiByte(CP_UTF8, 0, wstr, -1, NULL, 0, NULL, NULL);
	char* str = new char[len+1];
	memset(str, 0, len+1);
	WideCharToMultiByte(CP_UTF8, 0, wstr, -1, str, len, NULL, NULL);
	if(wstr) delete[] wstr;
	return str;
}

char* U2G(const char* utf8)
{
	int len = MultiByteToWideChar(CP_UTF8, 0, utf8, -1, NULL, 0);
	wchar_t* wstr = new wchar_t[len+1];
	memset(wstr, 0, len+1);
	MultiByteToWideChar(CP_UTF8, 0, utf8, -1, wstr, len);
	len = WideCharToMultiByte(CP_ACP, 0, wstr, -1, NULL, 0, NULL, NULL);
	char* str = new char[len+1];
	memset(str, 0, len+1);
	WideCharToMultiByte(CP_ACP, 0, wstr, -1, str, len, NULL, NULL);
	if(wstr) delete[] wstr;
	return str;
}

无论是GB2312到UTF-8的转换，还是UTF-8到GB2312的转换，都需要注意的是在使用字符串后，需要删除字符串指针。这是因为以上两个方法返回的是字符串指针，如果没有删除将会内存泄漏，可别说我没提醒你哦