In OS X, there is a command-line utility called security which is designed to access the Keychain. It can return the password of an entry in the Keychain, which is what I'm trying to do. When I run security find-internet-password -ga an_entry | grep "password" I get the following output, as expected:
在OS X中，有一个名为security的命令行实用程序，用于访问密钥链。它可以返回键链中条目的密码，这就是我要做的。当我运行安全查找-internet-password -ga an_entry | grep“password”时，我得到如下输出，如预期:
password: "apassword123"
I would like to extract the text between the quotes. grep, specifically pcregrep, should work but doesn't:
我想在引号之间提取文本。grep，尤其是pcregrep，应该有效，但没有:
echo 'password: "apassword123"' | pcregrep -o '^password:\s"(?!_)\K[^"]+'
Returns:
返回:
apassword123
As expected, but:
正如所料,但是:
security find-internet-password -ga anentry | pcregrep -o '^password:\s"(?!_)\K[^"]+'
Returns:
返回:
password: "apassword123"
Which is absurd.
这是荒谬的。
1 个解决方案
#1
2
Your output actually doesn't get through the grep as it's on stderr. You should be able to do this by redirecting the stderr to stdout like
您的输出实际上没有通过grep，因为它在stderr上。您应该能够通过像这样将stderr重定向到stdout来实现这一点
security find-internet-password -ga anentry 2>&1 | pcregrep -o '^password:\s"(?!_)\K[^"]+'
#1
2
Your output actually doesn't get through the grep as it's on stderr. You should be able to do this by redirecting the stderr to stdout like
您的输出实际上没有通过grep，因为它在stderr上。您应该能够通过像这样将stderr重定向到stdout来实现这一点
security find-internet-password -ga anentry 2>&1 | pcregrep -o '^password:\s"(?!_)\K[^"]+'