将节点附加到现有的xml-Java

时间:2020-12-01 14:05:39

I have seen the same question being answered for vb and c#, but i need a Java best solution for appending nodes to an xml. Will xpath help? I have

我已经看到了针对vb和c#的相同问题,但是我需要一个Java最佳解决方案来将节点附加到xml。请问xpath有帮助吗?我有

<A>
  <B>
    <c>1<c/>
    <d>2<d/>
    <e>3<e/>
  </B>
  <B>
    <c>1<c/>
    <d>2<d/>
    <e>3<e/>
  </B>
</A>

Need to append another

需要追加另一个

<B>
   <c>11<c/>
   <d>21<d/>
   <e>31<e/>
</B>

3 个解决方案

#1


13  

XPath will help you to find nodes, but not really append them. I don't think you'd find it particularly useful here.

XPath将帮助您查找节点,但不会真正附加它们。我不认为你在这里发现它特别有用。

Which XML API are you using? If it's the W3C DOM (urgh) then you'd do something like:

您使用的是哪种XML API?如果它是W3C DOM(urgh)那么你会做类似的事情:

Element newB = document.createElement("B");
Element newC = document.createElement("c");
newC.setTextContent("11");
Element newD = document.createElement("d");
newD.setTextContent("21");
Element newE = document.createElement("e");
newE.setTextContent("31");
newB.appendChild(newC);
newB.appendChild(newD);
newB.appendChild(newE);
document.getDocumentElement().appendChild(newB);

#2


2  

The most strait-forward way is that you parse, using Sax or Dom, all the files into a data structure, for example an A class which has a B class with members of C,D,E class in your case.

最直接的方法是使用Sax或Dom将所有文件解析为数据结构,例如A类,其中包含一个B类,其中包含C,D,E类的成员。

And output the data structure back to XML.

并将数据结构输出回XML。

#3


0  

You may want to use XMLModier of vtd-xml to do it in a cool way, which is to append the byte content directly... You just need to call XMLModier's insertAfterElement()... below is a link to the code sample: Incrementally Modify XML in Java:

您可能希望使用vtd-xml的XMLModier以一种很酷的方式执行它,即直接附加字节内容...您只需要调用XMLModier的insertAfterElement()...下面是代码示例的链接:在Java中增量修改XML:

import com.ximpleware.*;
import java.io.*;

public class ModifyXML {
     public static void main(String[] s) throws Exception{
        VTDGen vg = new VTDGen(); // Instantiate VTDGen
        XMLModifier xm = new XMLModifier(); //Instantiate XMLModifier
        if (vg.parseFile("old.xml",false)){
             VTDNav vn = vg.getNav();
             xm.bind(vn);

             // first update the value of attr
             int i = vn.getAttrVal("attr");
             if (i!=-1){
                  xm.updateToken(i,"value");
             }

             // navigate to <a>
            if (vn.toElement(VTDNav.FC,"a")) {
                  // update the text content of <a>
                   i=vn.getText();
                   if (i!=-1){
                      xm.updateToken(i," new content ");
                   }
                   // insert an element before <a> (which is the cursor element)
                   xm.insertBeforeElement("<b/>\n\t");

                   // insert an element after <a> (which is the cursor element)
                   xm.insertAfterElement("\n\t<c/>");
            }

            xm.output(new FileOutputStream("new.xml"));
         }
     }

}

#1


13  

XPath will help you to find nodes, but not really append them. I don't think you'd find it particularly useful here.

XPath将帮助您查找节点,但不会真正附加它们。我不认为你在这里发现它特别有用。

Which XML API are you using? If it's the W3C DOM (urgh) then you'd do something like:

您使用的是哪种XML API?如果它是W3C DOM(urgh)那么你会做类似的事情:

Element newB = document.createElement("B");
Element newC = document.createElement("c");
newC.setTextContent("11");
Element newD = document.createElement("d");
newD.setTextContent("21");
Element newE = document.createElement("e");
newE.setTextContent("31");
newB.appendChild(newC);
newB.appendChild(newD);
newB.appendChild(newE);
document.getDocumentElement().appendChild(newB);

#2


2  

The most strait-forward way is that you parse, using Sax or Dom, all the files into a data structure, for example an A class which has a B class with members of C,D,E class in your case.

最直接的方法是使用Sax或Dom将所有文件解析为数据结构,例如A类,其中包含一个B类,其中包含C,D,E类的成员。

And output the data structure back to XML.

并将数据结构输出回XML。

#3


0  

You may want to use XMLModier of vtd-xml to do it in a cool way, which is to append the byte content directly... You just need to call XMLModier's insertAfterElement()... below is a link to the code sample: Incrementally Modify XML in Java:

您可能希望使用vtd-xml的XMLModier以一种很酷的方式执行它,即直接附加字节内容...您只需要调用XMLModier的insertAfterElement()...下面是代码示例的链接:在Java中增量修改XML:

import com.ximpleware.*;
import java.io.*;

public class ModifyXML {
     public static void main(String[] s) throws Exception{
        VTDGen vg = new VTDGen(); // Instantiate VTDGen
        XMLModifier xm = new XMLModifier(); //Instantiate XMLModifier
        if (vg.parseFile("old.xml",false)){
             VTDNav vn = vg.getNav();
             xm.bind(vn);

             // first update the value of attr
             int i = vn.getAttrVal("attr");
             if (i!=-1){
                  xm.updateToken(i,"value");
             }

             // navigate to <a>
            if (vn.toElement(VTDNav.FC,"a")) {
                  // update the text content of <a>
                   i=vn.getText();
                   if (i!=-1){
                      xm.updateToken(i," new content ");
                   }
                   // insert an element before <a> (which is the cursor element)
                   xm.insertBeforeElement("<b/>\n\t");

                   // insert an element after <a> (which is the cursor element)
                   xm.insertAfterElement("\n\t<c/>");
            }

            xm.output(new FileOutputStream("new.xml"));
         }
     }

}