XSLT在输出文件中注入不需要的命名空间

I've seen similar questions, but it is still unclear to me. I don't want the "n1" namespace to appear in the attribute of the node in the output file. But I had to create the "n1" namespace in the xslt file in order to get xpath to work. Thank you.

我见过类似的问题，但我现在还不清楚。我不希望“n1”命名空间出现在输出文件中节点的属性中。但我必须在xslt文件中创建“n1”命名空间才能使xpath正常工作。谢谢。

XSLT:

XSLT：

   <xsl:stylesheet version="1.0" 
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:n1="http://www.spicefactory.org/parsley"
        xmlns="http://www.spicefactory.org/parsley"
        >

    <xsl:output method="xml" indent="no"/>

    <xsl:template match="node()|@*">
         <xsl:copy>
           <xsl:apply-templates select="node()|@*"/>
         </xsl:copy>
     </xsl:template>

     <xsl:template match="n1:object[@type='mytype1']">
      <object  type="mytype2">
        <xsl:apply-templates select="node()"/>
      </object>
     </xsl:template>

EXCERPT FROM OUTPUT XML FILE:

从OUTPUT XML文件中获取：

<object type="mytype2" xmlns:n1="http://www.spicefactory.org/parsley">

1 个解决方案

#1

Use exclude-result-prefixes attribute on <xsl:stylesheet> element.

在 元素上使用exclude-result-prefixes属性。 ：stylesheet>

<xsl:stylesheet version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:n1="http://www.spicefactory.org/parsley"
    xmlns="http://www.spicefactory.org/parsley"
    exclude-result-prefixes="n1"
    >