I want to select the data and then store it's information inside of a variable. I feel this is very simple but I can't seem to get it to do it. When I run the below code the result is blank.
我想选择数据,然后将其信息存储在变量中。我觉得这很简单,但我似乎无法做到这一点。当我运行以下代码时,结果为空。
Thanks for any help.
谢谢你的帮助。
$sql = "SELECT `$dateName` FROM `$user` WHERE hour=1";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$x = $row["`$dateName`"];
echo $x;
}
}
Here is my Create Table code:
这是我的创建表代码:
/* CREATE TABLE FOR NEW USER */
$sql = "CREATE TABLE `$newUser` (
hour INT(6) NOT NULL
)";
/* CHECK CREATION */
if ($conn->query($sql) === TRUE) {
} else {
echo "Error creating table: " . $conn->error . ".<br><br>";
}
/* ADD TABLE FOR TODAYS DATE */
$sql = "ALTER TABLE `$user`
ADD `$dateName` text";
if ($conn->query($sql) === TRUE) {
echo "Todays Date entered!";
} else {
echo "Date already Exists" . "<br><br>";
}
1 个解决方案
#1
1
$x will always be empty because of the ` you're adding to the key when you access $row:
$ x将始终为空,因为当您访问$ row时,您正在添加密钥:
$x = $row["`$dateName`"];
^ ^ remove ticks (You can also remove ")
#1
1
$x will always be empty because of the ` you're adding to the key when you access $row:
$ x将始终为空,因为当您访问$ row时,您正在添加密钥:
$x = $row["`$dateName`"];
^ ^ remove ticks (You can also remove ")