I have the following getJSON
which was working fine. I decided I wanted to be able to change the data shown on the page based on what the user selected. I have a function that sets a cookie based on the user selection. I want to take the value of this cookie and use it to get a specific value from the JSON object.
我有以下getJSON工作正常。我决定我希望能够根据用户选择的内容更改页面上显示的数据。我有一个功能,根据用户选择设置cookie。我想获取此cookie的值并使用它从JSON对象获取特定值。
The value of the cookie is retrieved and stored in cohort1
.
检索cookie的值并将其存储在cohort1中。
$.getJSON('all_get_login.php?cat_code=stocks&sortvalue=value&sortorder=asc', function(data) {
$.each(data, function(key, val) {
if (val.value == "Yes") {
var cohort1 = readCookie('cohort_id_1');
console.log(cohort1); //gives expected result
var databaseYes = val.cohort1; //THIS LINE IS THE PROBLEM
var databaseNo = 100 - databaseYes;
$("#yes_stocks_db").append(databaseYes + "%");
$("#no_stocks_db").append(databaseNo + "%");
});
});
My JSON object looks like this:
我的JSON对象如下所示:
[
{
"cat_code": "stocks",
"group": "fin",
"main_grouping": "Financial",
"highest_level": "Financial",
"category": "Invests in Stocks and Bonds",
"value": "No",
"database_percent": "38.90",
"cohort_1": "43.88",
"cohort_2": "27.66",
"national_percent": "30.16"
},
{
"cat_code": "stocks",
"group": "fin",
"main_grouping": "Financial",
"highest_level": "Financial",
"category": "Invests in Stocks and Bonds",
"value": "Yes",
"database_percent": "61.10",
"cohort_1": "56.37",
"cohort_2": "72.34",
"national_percent": "70.10"
}
]
Here's the problem: in the line in my getJSON
that has this var databaseYes= val.cohort1;
, the script is looking for something in the JSON object that matches "cohort1", which will never be in the object. What I need in here is the value of the var cohort1
and not the actual text "cohort1". How can I change this line to accommodate that?
这是问题所在:在我的getJSONt行中有这个var databaseYes = val.cohort1;,脚本在JSON对象中寻找匹配“cohort1”的东西,它永远不会出现在对象中。我在这里需要的是var cohort1的值而不是实际的文本“cohort1”。如何更改此行以适应这种情况?
1 个解决方案
#1
2
You can use []
object notation to pass a variable as a property name.
您可以使用[]对象表示法将变量作为属性名称传递。
var cohort1 ='foo';
var databaseYes = val[cohort1];
This is the equivalent of val.foo
这相当于val.foo
#1
2
You can use []
object notation to pass a variable as a property name.
您可以使用[]对象表示法将变量作为属性名称传递。
var cohort1 ='foo';
var databaseYes = val[cohort1];
This is the equivalent of val.foo
这相当于val.foo