I'm a nube to more than just bash, however; I've written a bash script that will execute my cmake, make, and c++ executable.
然而,我不仅仅是一个胆怯,不仅仅是狂欢。我写了一个bash脚本,它将执行我的cmake,make和c ++可执行文件。
#! /bin/bash
cmake .
make
./pcl_visualizer_demo <-- This is my executable
This works great except when my code fails to compile it executes the old executable and leaves me with a mess. I was hoping to put the output of make into an if statement that only runs the executable when make is successful. I've tried a great many bash things from other posts here on *. Some of the problems seem to be that the output of make is not a string for example:
这很好用,除非我的代码无法编译它执行旧的可执行文件并让我一团糟。我希望将make的输出放入if语句中,该语句仅在make成功时运行可执行文件。我在*上尝试了很多其他帖子中的bash东西。一些问题似乎是make的输出不是一个字符串,例如:
OUTPUT = make
echo $OUTPUT
gives:
[100%] Built target pcl_visualizer_demo
But fails to work with:
但未能合作:
if [`expr match "$OUTPUT" '[100%] -eq 5]; then ./pcl_visulizer_demo; fi
Not to mention I think there may be more than one thing wrong with this line. I also tried:
更不用说我认为这条线可能不止一件事。我也尝试过:
if [diff <(echo "$OUTPUT") <(echo '[100%] Built target pcl_visualizer_demo' -n]; then ./pcl_visulizer_demo; fi
Again it could be that I'm not implementing it right. Any help
再次,可能是我没有正确实施它。任何帮助
4 个解决方案
#1
18
Just check the exit code of make:
只需检查make的退出代码:
cmake . || exit 1
make || exit 1
./pcl_visualizer_demo
#2
4
You could use
你可以用
set -e
at the beginning of your shell script
在shell脚本的开头
#!/bin/bash
set -e
cmake .
make
./pcl_visualizer_demo
From 'help set'
来自'帮助集'
-e Exit immediately if a command exits with a non-zero status.
Which by default means: on any error
默认情况下,这意味着:任何错误
#3
2
You should probably check the exit code of make e.g.
您应该检查make的退出代码,例如
if [ $? -eq 0 ]
then
echo "Successfully made"
else
echo "Could not compile" >&2
fi
and exit appropriately. By convention, an exit code of 0 indicates success. If you have multiple executables and you want to bail out if any return a non-zero exit code, you can tell bash to do just that with the -e option e.g.
并适当退出。按照惯例,退出代码为0表示成功。如果你有多个可执行文件,如果有任何返回非零退出代码你想要拯救,你可以告诉bash使用-e选项做到这一点,例如
#!/usr/bin/bash -e
Just make sure that the executables (make and cmake) follow this convention. See here for more information on exit codes.
只需确保可执行文件(make和cmake)遵循此约定。有关退出代码的详细信息,请参见此处
#4
0
You could try to determine what the 'exit status' of your previous bash command was using '$?'. Usually, a build that did not succeed will exit with a non zero status. Double check that this is true in your case by echo-ing '$?'
您可以尝试确定先前bash命令的“退出状态”是使用“$?”。通常,未成功的构建将以非零状态退出。通过回显“$?”来仔细检查这是否属实。
Then use an normal if statement to proceed correctly.
然后使用正常的if语句正确继续。
$? reads the exit status of the last command executed. After a function returns, $? gives the exit status of the last command executed in the function. This is Bash's way of giving functions a "return value." . . .
After a script terminates, a $? from the command-line gives the exit status of the script, that is, the last command executed in the script, which is, by convention, 0 on success or an integer in the range 1 - 255 on error.$?读取上次执行的命令的退出状态。函数返回后,$?给出函数中执行的最后一个命令的退出状态。这是Bash赋予函数“返回值”的方式。 。 。 。脚本终止后,$?从命令行给出脚本的退出状态,即脚本中执行的最后一个命令,按惯例,成功时为0,或者出错时为1 - 255的整数。
#1
18
Just check the exit code of make:
只需检查make的退出代码:
cmake . || exit 1
make || exit 1
./pcl_visualizer_demo
#2
4
You could use
你可以用
set -e
at the beginning of your shell script
在shell脚本的开头
#!/bin/bash
set -e
cmake .
make
./pcl_visualizer_demo
From 'help set'
来自'帮助集'
-e Exit immediately if a command exits with a non-zero status.
Which by default means: on any error
默认情况下,这意味着:任何错误
#3
2
You should probably check the exit code of make e.g.
您应该检查make的退出代码,例如
if [ $? -eq 0 ]
then
echo "Successfully made"
else
echo "Could not compile" >&2
fi
and exit appropriately. By convention, an exit code of 0 indicates success. If you have multiple executables and you want to bail out if any return a non-zero exit code, you can tell bash to do just that with the -e option e.g.
并适当退出。按照惯例,退出代码为0表示成功。如果你有多个可执行文件,如果有任何返回非零退出代码你想要拯救,你可以告诉bash使用-e选项做到这一点,例如
#!/usr/bin/bash -e
Just make sure that the executables (make and cmake) follow this convention. See here for more information on exit codes.
只需确保可执行文件(make和cmake)遵循此约定。有关退出代码的详细信息,请参见此处
#4
0
You could try to determine what the 'exit status' of your previous bash command was using '$?'. Usually, a build that did not succeed will exit with a non zero status. Double check that this is true in your case by echo-ing '$?'
您可以尝试确定先前bash命令的“退出状态”是使用“$?”。通常,未成功的构建将以非零状态退出。通过回显“$?”来仔细检查这是否属实。
Then use an normal if statement to proceed correctly.
然后使用正常的if语句正确继续。
$? reads the exit status of the last command executed. After a function returns, $? gives the exit status of the last command executed in the function. This is Bash's way of giving functions a "return value." . . .
After a script terminates, a $? from the command-line gives the exit status of the script, that is, the last command executed in the script, which is, by convention, 0 on success or an integer in the range 1 - 255 on error.$?读取上次执行的命令的退出状态。函数返回后,$?给出函数中执行的最后一个命令的退出状态。这是Bash赋予函数“返回值”的方式。 。 。 。脚本终止后,$?从命令行给出脚本的退出状态,即脚本中执行的最后一个命令,按惯例,成功时为0,或者出错时为1 - 255的整数。