I want to be able to loop through a list of files that match a particular pattern. I can get unix to list these files using ls and egrep with a regular expression, but I cannot find a way to turn this into an iterative process. I suspect that using ls is not the answer. Any help would be gratefully received.
我希望能够循环遍历与特定模式匹配的文件列表。我可以让unix使用带有正则表达式的ls和egrep列出这些文件,但我找不到将其转换为迭代过程的方法。我怀疑使用ls不是答案。我们将非常感激地提供任何帮助。
My current ls command looks as follows:
我当前的ls命令如下所示:
ls | egrep -i 'MYFILE[0-9][0-9]([0][1-9]|1[0-2])([0][1-9]|[12][0-9]|[3][01]).dat'
I would expect the above to match:
我希望上面的内容匹配:
- MYFILE160418.dat
- myFILE170312.DAT
- MyFiLe160416.DaT
but not:
- MYOTHERFILE150202.DAT
- Myfile.dat
- myfile.csv
Thanks,
Paul.
2 个解决方案
#1
5
You can use (GNU) find
with the regex search option instead of parsing ls
.
您可以使用(GNU)查找正则表达式搜索选项而不是解析ls。
find . -regextype "egrep" \
-iregex '.*/MYFILE[0-9][0-9]([0][1-9]|1[0-2])([0][1-9]|[12][0-9]|[3][01]).dat' \
-exec [[whatever you want to do]] {} \;
Where [[whatever you want to do]]
is the command you want to perform on the names of the files.
其中[[您想要做什么]]是您要对文件名称执行的命令。
From the man page
从手册页
-regextype type Changes the regular expression syntax understood by -regex and -iregex tests which occur later on the command line. Currently-implemented types are emacs (this is the default),posix-awk, posix-basic, posix-egrep and posix-extended. -regex pattern File name matches regular expression pattern. This is a match on the whole path, not a search. For example, to match a file named `./fubar3', you can use the regular expression `.*bar.' or `.*b.*3', but not `f.*r3'. The regular expressions understood by find are by default Emacs Regular Expressions, but this can be changed with the -regextype option. -iregex pattern Like -regex, but the match is case insensitive.
#2
2
Based on the link Andy K provided I have used the following to loop based on my matching criteria:
基于Andy K提供的链接,我使用以下内容根据我的匹配条件进行循环:
for i in $(ls | egrep -i 'MYFILE[0-9][0-9]([0][1-9]|1[0-2])([0][1-9]|[12][0-9]|[3][01]).dat' ); do
echo item: $i;
done
#1
5
You can use (GNU) find
with the regex search option instead of parsing ls
.
您可以使用(GNU)查找正则表达式搜索选项而不是解析ls。
find . -regextype "egrep" \
-iregex '.*/MYFILE[0-9][0-9]([0][1-9]|1[0-2])([0][1-9]|[12][0-9]|[3][01]).dat' \
-exec [[whatever you want to do]] {} \;
Where [[whatever you want to do]]
is the command you want to perform on the names of the files.
其中[[您想要做什么]]是您要对文件名称执行的命令。
From the man page
从手册页
-regextype type Changes the regular expression syntax understood by -regex and -iregex tests which occur later on the command line. Currently-implemented types are emacs (this is the default),posix-awk, posix-basic, posix-egrep and posix-extended. -regex pattern File name matches regular expression pattern. This is a match on the whole path, not a search. For example, to match a file named `./fubar3', you can use the regular expression `.*bar.' or `.*b.*3', but not `f.*r3'. The regular expressions understood by find are by default Emacs Regular Expressions, but this can be changed with the -regextype option. -iregex pattern Like -regex, but the match is case insensitive.
#2
2
Based on the link Andy K provided I have used the following to loop based on my matching criteria:
基于Andy K提供的链接,我使用以下内容根据我的匹配条件进行循环:
for i in $(ls | egrep -i 'MYFILE[0-9][0-9]([0][1-9]|1[0-2])([0][1-9]|[12][0-9]|[3][01]).dat' ); do
echo item: $i;
done