I want to delete 3 files in list_file_to_delete
but I do not know what is the path to put to "path to three files here"?. Do I need for loop/for in/forEach function to delete all or just need a string with 3 paths likely var string = "...a1.jpg, ...a2.jpg,...a3.jpg"
? Thanks in advance
我想在list_file_to_delete中删除3个文件,但我不知道在这里放到“三个文件的路径”的路径是什么?我是否需要循环/ for / forEach函数来删除所有或只需要一个包含3条路径的字符串var string =“... a1.jpg,... a2.jpg,... a3.jpg”?提前致谢
in delete.js
file
在delete.js文件中
var list_file_to_delete = ["/images/a1.jpg", "/images/a2.jpg", "/images/a3.jpg"]
fs.unlink(path to three files here, function(err) {console.log("success")})
this is myapp
directory
这是myapp目录
myapp
/app
/js
delete.js
/public
/images
a1.jpg
a2.jpg
a3.jpg
server.js
1 个解决方案
#1
16
fs.unlink
takes a single file, so unlink each element:
fs.unlink采用单个文件,因此取消链接每个元素:
list_of_files.forEach(function(filename) {
fs.unlink(filename);
});
or, if you need sequential, but asynchronous deletes you can use the following ES5 code:
或者,如果您需要顺序但异步删除,则可以使用以下ES5代码:
(function next(err, list) {
if (err) {
return console.error("error in next()", err);
}
if (list.length === 0) {
return;
}
var filename = list.splice(0,1)[0];
fs.unlink(filename, function(err, result) {
next(err, list);
});
}(null, list_of_files.slice()));
#1
16
fs.unlink
takes a single file, so unlink each element:
fs.unlink采用单个文件,因此取消链接每个元素:
list_of_files.forEach(function(filename) {
fs.unlink(filename);
});
or, if you need sequential, but asynchronous deletes you can use the following ES5 code:
或者,如果您需要顺序但异步删除,则可以使用以下ES5代码:
(function next(err, list) {
if (err) {
return console.error("error in next()", err);
}
if (list.length === 0) {
return;
}
var filename = list.splice(0,1)[0];
fs.unlink(filename, function(err, result) {
next(err, list);
});
}(null, list_of_files.slice()));