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- What is the difference between a deep copy and a shallow copy? 30 answers
- 深拷贝和浅拷贝的区别是什么?30的答案
According the MDN documentation calling array.slice()
will create a shallow copy of the array.
根据调用array.slice()的MDN文档,将创建数组的一个浅拷贝。
See this MDN link for slice().
请参见此MDN链接的slice()。
However, if I run a simple test as such in the console:
但是,如果我在控制台运行一个简单的测试:
var test = [[1,2,3],7,8,9];
var shallow_copy = test.slice();
and inspect shallow_copy, I can see that the entire 2 dimensional array appears to be copied over.
检查浅拷贝,我可以看到整个二维数组被复制过来。
What is the difference between a shallow copy and a deep copy? If I were to guess, I would have called this a deep copy.
浅拷贝和深拷贝之间的区别是什么?如果我猜的话,我就会把这个叫做深度拷贝。
2 个解决方案
#1
20
To see the difference, try:
要看到区别,试着:
shallow_copy[0][2] = 4;
console.dir(test);
You'll see that test
has been modified! This is because while you may have copied the values to the new array, the nested array is still the same one.
您将看到测试被修改了!这是因为虽然您可能已经将值复制到新的数组中,但嵌套的数组仍然是相同的。
A deep copy would recursively perform shallow copies until everything is a new copy of the original.
深度拷贝会递归地执行浅拷贝,直到所有东西都是原始拷贝的新拷贝。
#2
1
Basically you're just getting a reference to the original variable/array. Changing the reference will also change the original array. You need to loop over the values of the original array and form a copy.
基本上你只是得到了对原始变量/数组的引用。更改引用也将更改原始数组。您需要对原始数组的值进行循环并形成一个副本。
Consider this example:
考虑一下这个例子:
var orig = { a: 'A', b: 'B', c: 'C' };
Let's say you want to create a duplicate of this, so that even if you change the original values, you can always return to the original.
假设你想要创建一个这个的副本,这样即使你改变了原始值,你仍然可以返回原始值。
I can do this:
我可以这样做:
var dup = orig; //Shallow copy!
If we change a value:
如果我们改变一个值:
dup.a = 'Apple';
This statement will also change a
from orig
, since we have a shallow copy, or a reference to var orig
. This means, you're losing the original data as well.
这个语句也会从orig中改变a,因为我们有一个浅拷贝,或者是对var orig的引用。这意味着,您也将丢失原始数据。
But, creating a brand new variable by using the properties from the original orig
variable, you can create a deep copy.
但是,通过使用来自原始orig变量的属性创建一个全新的变量,您可以创建一个深度副本。
var dup = { a: orig.a, b: orig.b, c: orig.c }; //Deep copy!
Now if you change dup.a
, it will only affect dup
and not orig
.
现在如果你改变dup。a,它只会影响dup,不会影响orig。
#1
20
To see the difference, try:
要看到区别,试着:
shallow_copy[0][2] = 4;
console.dir(test);
You'll see that test
has been modified! This is because while you may have copied the values to the new array, the nested array is still the same one.
您将看到测试被修改了!这是因为虽然您可能已经将值复制到新的数组中,但嵌套的数组仍然是相同的。
A deep copy would recursively perform shallow copies until everything is a new copy of the original.
深度拷贝会递归地执行浅拷贝,直到所有东西都是原始拷贝的新拷贝。
#2
1
Basically you're just getting a reference to the original variable/array. Changing the reference will also change the original array. You need to loop over the values of the original array and form a copy.
基本上你只是得到了对原始变量/数组的引用。更改引用也将更改原始数组。您需要对原始数组的值进行循环并形成一个副本。
Consider this example:
考虑一下这个例子:
var orig = { a: 'A', b: 'B', c: 'C' };
Let's say you want to create a duplicate of this, so that even if you change the original values, you can always return to the original.
假设你想要创建一个这个的副本,这样即使你改变了原始值,你仍然可以返回原始值。
I can do this:
我可以这样做:
var dup = orig; //Shallow copy!
If we change a value:
如果我们改变一个值:
dup.a = 'Apple';
This statement will also change a
from orig
, since we have a shallow copy, or a reference to var orig
. This means, you're losing the original data as well.
这个语句也会从orig中改变a,因为我们有一个浅拷贝,或者是对var orig的引用。这意味着,您也将丢失原始数据。
But, creating a brand new variable by using the properties from the original orig
variable, you can create a deep copy.
但是,通过使用来自原始orig变量的属性创建一个全新的变量,您可以创建一个深度副本。
var dup = { a: orig.a, b: orig.b, c: orig.c }; //Deep copy!
Now if you change dup.a
, it will only affect dup
and not orig
.
现在如果你改变dup。a,它只会影响dup,不会影响orig。