I'm working on creating a website similar to oc.tc. The website system, not the content. Anyway, if you notice how you can do oc.tc/itunes89(Or oc.tc/anyregistereduser) I would like to know how to do that. I don't think there creating pages for everyone, I think there dynamically doing this.
我正在创建一个类似于oc.tc的网站。网站系统，而不是内容。无论如何，如果你注意到如何做oc.tc/itunes89（或oc.tc/anyregistereduser）我想知道如何做到这一点。我认为没有为每个人创建页面，我认为有动态这样做。
*I've already created a system, like username=user and id=12. I would like to know how to do that without triggering a 404 error.
*我已经创建了一个系统，比如username = user和id = 12。我想知道如何在不触发404错误的情况下执行此操作。
Thanks for your help.
谢谢你的帮助。
2 个解决方案
#1
2
Are you using Apache?
你在使用Apache吗？
If so, welcome to the amazing world of Apache's mod_rewrite. (http://httpd.apache.org/docs/current/mod/mod_rewrite.html)
如果是这样，欢迎来到Apache的mod_rewrite令人惊叹的世界。 （http://httpd.apache.org/docs/current/mod/mod_rewrite.html）
Here's the basic concept: you define rules that "rewrite" a URL like oc.tc/itunes89 into oc.tc/show_user.php?username=itunes89 (or whatever you want).
这是基本概念：您可以定义将oc.tc/itunes89等URL“重写”为oc.tc/show_user.php?username=itunes89（或任何您想要的）的规则。
This is an excellent guide to mod_rewrite: http://www.sitepoint.com/guide-url-rewriting-2/. Let me know if you have a specific question or problem implementing it.
这是mod_rewrite的优秀指南：http：//www.sitepoint.com/guide-url-rewriting-2/。如果您有实施它的具体问题或问题，请告诉我。
#2
1
For Apache Tomcat, you can do such things if you map a servlet to a certain URL pattern, and then show the correct page. A tutorial that shows an example can be found here. Together with the source code of the JSPServlet ( here ), you can put together your own servlet that does what you want. I think the method used to retrieve the path is HttpRequest.getServletPath() and HttpRequest.getPathInfo(), but you best just try to understand the source code i pointed to (the service(..) method is the one that is called when you access the servlet).
对于Apache Tomcat，如果将servlet映射到某个URL模式，然后显示正确的页面，则可以执行此类操作。可以在此处找到显示示例的教程。与JSPServlet的源代码（此处）一起，您可以将自己的servlet放在一起，完成您想要的操作。我认为用于检索路径的方法是HttpRequest.getServletPath（）和HttpRequest.getPathInfo（），但您最好只是尝试理解我指向的源代码（service（..）方法是在调用时调用的方法）你访问servlet）。
#1
2
Are you using Apache?
你在使用Apache吗？
If so, welcome to the amazing world of Apache's mod_rewrite. (http://httpd.apache.org/docs/current/mod/mod_rewrite.html)
如果是这样，欢迎来到Apache的mod_rewrite令人惊叹的世界。 （http://httpd.apache.org/docs/current/mod/mod_rewrite.html）
Here's the basic concept: you define rules that "rewrite" a URL like oc.tc/itunes89 into oc.tc/show_user.php?username=itunes89 (or whatever you want).
这是基本概念：您可以定义将oc.tc/itunes89等URL“重写”为oc.tc/show_user.php?username=itunes89（或任何您想要的）的规则。
This is an excellent guide to mod_rewrite: http://www.sitepoint.com/guide-url-rewriting-2/. Let me know if you have a specific question or problem implementing it.
这是mod_rewrite的优秀指南：http：//www.sitepoint.com/guide-url-rewriting-2/。如果您有实施它的具体问题或问题，请告诉我。
#2
1
For Apache Tomcat, you can do such things if you map a servlet to a certain URL pattern, and then show the correct page. A tutorial that shows an example can be found here. Together with the source code of the JSPServlet ( here ), you can put together your own servlet that does what you want. I think the method used to retrieve the path is HttpRequest.getServletPath() and HttpRequest.getPathInfo(), but you best just try to understand the source code i pointed to (the service(..) method is the one that is called when you access the servlet).
对于Apache Tomcat，如果将servlet映射到某个URL模式，然后显示正确的页面，则可以执行此类操作。可以在此处找到显示示例的教程。与JSPServlet的源代码（此处）一起，您可以将自己的servlet放在一起，完成您想要的操作。我认为用于检索路径的方法是HttpRequest.getServletPath（）和HttpRequest.getPathInfo（），但您最好只是尝试理解我指向的源代码（service（..）方法是在调用时调用的方法）你访问servlet）。