文件格式如图所示:
解析代码如下:
#include <stdio.h> #include <stdint.h> #include <stdlib.h> struct WAV_Format { uint32_t ChunkID; /* "RIFF" */ uint32_t ChunkSize; /* 36 + Subchunk2Size */ uint32_t Format; /* "WAVE" */ /* sub-chunk "fmt" */ uint32_t Subchunk1ID; /* "fmt " */ uint32_t Subchunk1Size; /* 16 for PCM */ uint16_t AudioFormat; /* PCM = 1*/ uint16_t NumChannels; /* Mono = 1, Stereo = 2, etc. */ uint32_t SampleRate; /* 8000, 44100, etc. */ uint32_t ByteRate; /* = SampleRate * NumChannels * BitsPerSample/8 */ uint16_t BlockAlign; /* = NumChannels * BitsPerSample/8 */ uint16_t BitsPerSample; /* 8bits, 16bits, etc. */ /* sub-chunk "data" */ uint32_t Subchunk2ID; /* "data" */ uint32_t Subchunk2Size; /* data size */ }; int main(void) { FILE *fp = NULL; struct WAV_Format wav; fp = fopen("test.wav", "rb"); if (!fp) { printf("can't open audio file\n"); exit(1); } fread(&wav, 1, sizeof(struct WAV_Format), fp); printf("ChunkID \t%x\n", wav.ChunkID); printf("ChunkSize \t%d\n", wav.ChunkSize); printf("Format \t\t%x\n", wav.Format); printf("Subchunk1ID \t%x\n", wav.Subchunk1ID); printf("Subchunk1Size \t%d\n", wav.Subchunk1Size); printf("AudioFormat \t%d\n", wav.AudioFormat); printf("NumChannels \t%d\n", wav.NumChannels); printf("SampleRate \t%d\n", wav.SampleRate); printf("ByteRate \t%d\n", wav.ByteRate); printf("BlockAlign \t%d\n", wav.BlockAlign); printf("BitsPerSample \t%d\n", wav.BitsPerSample); printf("Subchunk2ID \t%x\n", wav.Subchunk2ID); printf("Subchunk2Size \t%d\n", wav.Subchunk2Size); fclose(fp); return 0; }
// 2016-09-22 add
ByteRate计算方法是SampleRate * NumChannels * BitsPerSample/8,那么这个公式计算出来的是1秒钟音频数据大小,单位为Byte,以44100、16bit、2通道为例,那么计算出来值为176400,根据总音频数据大小,可以得出播放时间的计算公式为Subchunk2Size / ByteRate。