由于套接字没有连接并且(当使用一个 sendto 调用发送数据报套接字时)没有提供地址，发送或接收数据的请求没有被接受。

服务端代码
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Net.Sockets;
using System.Net;
using System.Threading;

namespace 简易服务端 {
    class Program {
        static void Main(string[] args) {
            //声明服务端的socket
            showMsg("开启服务器....");
                Socket service = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
                IPEndPoint ipPoint = new IPEndPoint(IPAddress.Any, 50816);
                service.Bind(ipPoint);
                service.Listen(10);
                Thread th = new Thread(accept);
                showMsg("等待用户连接.....");
                th.Start(service);
        }
        //等待连接的好友
       static void accept(object obj) {
            
                Socket acceptService = obj as Socket;
                while (true) {
                    Console.WriteLine("===========");
                    acceptService.Accept();
                    Thread th = new Thread(receive);
                    th.Start(acceptService);
            }
           
        }

        //接受客户端的消息
       static void receive(object obj) {
                Socket receiveService = obj as Socket;
                while (true) {
                    byte[] by = new byte[1024 * 1024];
                    Console.WriteLine("=====接受到了-======");
                    int a = 0;
                    IPEndPoint ipP = new IPEndPoint(IPAddress.Parse("192.168.16.178"),50816);
                    EndPoint p=ipP;
                    a = receiveService.ReceiveFrom(by,ref p);
                    Console.WriteLine("=====接受到了======" + a);
                    if (a == 0) break;
                    showMsg(receiveService.RemoteEndPoint + "发来消息： " + Encoding.UTF8.GetString(by));
                }
        }
        //将内容显示到消息框当中
      static  void showMsg(string str) {
          Console.WriteLine(str+"\n");
        }
    }
}



------------------------------------------------------------------------------
客户端代码


using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Net.Sockets;
using System.Net;
using System.Threading;

namespace 简易服务端 {
    class Program {
        static void Main(string[] args) {
            //声明服务端的socket
            showMsg("开启服务器....");
                Socket service = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
                IPEndPoint ipPoint = new IPEndPoint(IPAddress.Any, 50816);
                service.Bind(ipPoint);
                service.Listen(10);
                Thread th = new Thread(accept);
                showMsg("等待用户连接.....");
                th.Start(service);
        }
        //等待连接的好友
       static void accept(object obj) {
            
                Socket acceptService = obj as Socket;
                while (true) {
                    Console.WriteLine("===========");
                    acceptService.Accept();
                    Thread th = new Thread(receive);
                    th.Start(acceptService);
            }
           
        }

        //接受客户端的消息
       static void receive(object obj) {
                Socket receiveService = obj as Socket;
                while (true) {
                    byte[] by = new byte[1024 * 1024];
                    Console.WriteLine("=====接受到了-======");
                    int a = 0;
                    IPEndPoint ipP = new IPEndPoint(IPAddress.Parse("192.168.16.178"),50816);
                    EndPoint p=ipP;
                    a = receiveService.ReceiveFrom(by,ref p);
                    Console.WriteLine("=====接受到了======" + a);
                    if (a == 0) break;
                    showMsg(receiveService.RemoteEndPoint + "发来消息： " + Encoding.UTF8.GetString(by));
                }
        }
        //将内容显示到消息框当中
      static  void showMsg(string str) {
          Console.WriteLine(str+"\n");
        }
    }
}

分别运行后出现这个状况


找了半天没有找到原因，求各位大神帮帮忙啊！！！

2 个解决方案

#1

找到原因了，就是那个Socket.Accept（）方法返回一个新的socket我没有接受用的还是原来的那个Socket所以才会出现这个原因

#2

楼主你怎么解决的。。我也遇到了这个问题。。但我是在数据发送的时候报错