Am trying to separate the path param and matrix param from the following uri string in jersey.
我试图将路径参数和矩阵参数与球衣中的以下uri字符串分开。
/flights/flightid;numberofseats=2/date.
Things I wanna separate following parameters using jersey
我希望使用泽西分离以下参数
- Flightid
- numberofseats
- date
I tried all this code to separate but am failing miserably.
我尝试将所有这些代码分开但是失败了。
@GET
@Path(value = "/flight/{flightid}/{date}")
@Produces(MediaType.TEXT_PLAIN)
public Response bookFlight(@MatrixParam("numberofseats") int numberOfSeats,
@PathParam(value = "flightid") int flightid,
@PathParam(value = "date") String date) {
//Logic
}
1 个解决方案
#1
0
All matrix param examples I know carry them at the and of the URI. In your case the regex derived from your Path
would eat up all URI parts and leave nothing for the @PathParam
to capture. See section 3.7.3 of the JAX-RS 2.0 Spec.
我知道的所有矩阵参数示例都在URI和URI处进行。在你的情况下,从你的Path派生的正则表达式会占用所有URI部分,并且不会为@PathParam留下任何东西。请参阅JAX-RS 2.0规范的3.7.3节。
If possible, move theses parameters to the end.
如果可能,将这些参数移到最后。
Or parse flightid (which would contain the matrix params, I think) in your own code.
或者在你自己的代码中解析flightid(我认为它包含矩阵参数)。
#1
0
All matrix param examples I know carry them at the and of the URI. In your case the regex derived from your Path
would eat up all URI parts and leave nothing for the @PathParam
to capture. See section 3.7.3 of the JAX-RS 2.0 Spec.
我知道的所有矩阵参数示例都在URI和URI处进行。在你的情况下,从你的Path派生的正则表达式会占用所有URI部分,并且不会为@PathParam留下任何东西。请参阅JAX-RS 2.0规范的3.7.3节。
If possible, move theses parameters to the end.
如果可能,将这些参数移到最后。
Or parse flightid (which would contain the matrix params, I think) in your own code.
或者在你自己的代码中解析flightid(我认为它包含矩阵参数)。